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2 years ago

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Sara threw her math book off a building . The height of the book, seconds after being thrownis modeled by the equation below. Th

e height measured in feet. h(x)=-5(x+2)(x-7) what is the height of the book when it is thrown?

1 answer:

Vikentia [17]2 years ago

4 0

Answer: 70 ft

Step-by-step explanation:

Given

height of book is measured by the function is

$h(x)=-5(x+2)(x-7)$

when the book is thrown $x=0$

$\therefore h(x=0)=-5(0+2)(0-7)\\\Rightarrow h(x=0)=70\ ft$

The height of the book is $70\ ft$

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Sedaia [141]

Answer:

27/16

Step-by-step explanation:

this is because i added up 1/2 and 3/4 first, which gave me 1 1/4, and i converted this into just a single fraction without a whole number to make the adding easier for me which was 5/4.

(a whole number is the amount of times the bottom number of the fraction went into the top number so-... 4 goes into 5 one time which gives you a whole number of 1 and the fraction of 1/4. the 1 being left from the five.)

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2 years ago

Y is directly proportional to x,and y=216 when x=2. Find y when x=7.

makkiz [27]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=216\\
x=2
\end{cases}\implies 216=k2\implies \cfrac{216}{2}=k
\\\\\\
108=k\qquad therefore\qquad \boxed{y=108x}
\\\\\\
\textit{when x = 7, what is \underline{y}?}\qquad y=108(7)$

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3 years ago

For every $2 that Miguel saves his parents give him $4 if Miguel saves $60 how much money will his parents give him

Nastasia [14]

60/2 equals 30 then 30x4 is 120. Is parents give him a 120$

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11 months ago

Prove that the segments joining the midpoint of consecutive sides of an isosceles trapezoid form a rhombus.

sergiy2304 [10]

Answer:

See explanation

Step-by-step explanation:

a) To prove that DEFG is a rhombus, it is sufficient to prove that:

All the sides of the rhombus are congruent: $|DG|\cong |GF| \cong |EF| \cong |DE|$
The diagonals are perpendicular

Using the distance formula; $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$|DG|=\sqrt{(0-(-a-b))^2+(0-c)^2}$

$\implies |DG|=\sqrt{a^2+b^2+c^2+2ab}$

$|GF|=\sqrt{((a+b)-0)^2+(c-0)^2}$

$\implies |GF|=\sqrt{a^2+b^2+c^2+2ab}$

$|EF|=\sqrt{((a+b)-0)^2+(c-2c)^2}$

$\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}$

$|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}$

$\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}$

Using the slope formula; $m=\frac{y_2-y_1}{x_2-x_1}$

The slope of EG is $m_{EG}=\frac{2c-0}{0-0}$

$\implies m_{EG}=\frac{2c}{0}$

The slope of EG is undefined hence it is a vertical line.

The slope of DF is $m_{DF}=\frac{c-c}{a+b-(-a-b)}$

$\implies m_{DF}=\frac{0}{2a+2b)}=0$

The slope of DF is zero, hence it is a horizontal line.

A horizontal line meets a vertical line at 90 degrees.

Conclusion:

Since $|DG|\cong |GF| \cong |EF| \cong |DE|$ and $DF \perp FG$ , DEFG is a rhombus

b) Using the slope formula:

The slope of DE is $m_{DE}=\frac{2c-c}{0-(-a-b)}$

$m_{DE}=\frac{c}{a+b)}$

The slope of FG is $m_{FG}=\frac{c-0}{a+b-0}$

$\implies m_{FG}=\frac{c}{a+b}$

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3 years ago

Give a counterexample for the following

notsponge [240]

Answers: the answer is 1

Step-by-step explanation: 2+2=4

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