1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Basile [38]
3 years ago
5

At what value of x does the graph of the function f(x) have a vertical asymptote?

Mathematics
1 answer:
choli [55]3 years ago
3 0
It will have a vertical asymptote when the denominator approaches zero.

2x-6=0

2x=6

x=3

So the vertical asymptote is the vertical line x=3
You might be interested in
Eleanor can drive an average of 374 miles on one tank of gas. How many miles can she drive on 15 tanks of gas?
lidiya [134]
Well you would just multiply 374 by 15 and that would be your answer
8 0
3 years ago
Read 2 more answers
A swimming pool has about 603 cubic feet of water. The pool liner has a small hole and is leaking at a rate of 1.5 cubic feet ea
Readme [11.4K]

Answer:

Ruby’s function notation V(h) describes the volume of the pool after h number of hours. Hours is the independent variable and the total volume is the dependent variable.

Step-by-step explanation:

sample response

3 0
3 years ago
Read 2 more answers
How do you graph y=-1.5<img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20" id="TexFormula1" title=" x^{2} " alt=" x^{2} " align
lorasvet [3.4K]
y=-1.5 x^{2} +6 \\ \\ x=-3 \Rightarrow y=-1.5*(-3)^2+6 =-1.5*9+6=-13.5+6=-7.5\\ \\x=-2 \Rightarrow y=-1.5*(-2)^2+6 =-1.5*4+6=-6+6=0\\ \\x=-1 \Rightarrow y=-1.5*(-1)^2+6 =-1.5*1+6=-1.5+6=-4.5\\ \\x=0 \Rightarrow y=-1.5*0^2+6 =6

x=1 \Rightarrow y=-1.5*(1)^2+6 =-1.5+6=-4.5\\ \\ x= 2 \Rightarrow y=-1.5*2^2+6 =-1.5*4+6=-6+6=0\\ \\x=3 \Rightarrow y=-1.5*3^2+6 =-1.5*9+6=-13.5+6=-7.5


6 0
3 years ago
jobs gross pay is $400, from which $24.80 deducted for OASDI, $5.20 for Medicare, and $45 for income tax. what is her net pay? A
katrin2010 [14]
$24.80 + $5.20 + $45.00 = $75.00 the answer is B
7 0
3 years ago
Read 2 more answers
Determine which of the sets of vectors is linearly independent. A: The set where p1(t) = 1, p2(t) = t2, p3(t) = 3 + 3t B: The se
defon

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

p_{1}(t) = 1, p_{2}(t)= t^{2} and p_{3}(t) = 3 + 3\cdot t:

\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0

\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0

(\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0

The following system of linear equations is obtained:

\alpha_{1} + 3\cdot \alpha_{3} = 0

\alpha_{2} = 0

\alpha_{3} = 0

Whose solution is \alpha_{1} = \alpha_{2} = \alpha_{3} = 0, which means that the set of vectors is linearly independent.

p_{1}(t) = t, p_{2}(t) = t^{2} and p_{3}(t) = 2\cdot t + 3\cdot t^{2}

\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0

\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0

(\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0

The following system of linear equations is obtained:

\alpha_{1}+2\cdot \alpha_{3} = 0

\alpha_{2}+3\cdot \alpha_{3} = 0

Since the number of variables is greater than the number of equations, let suppose that \alpha_{3} = k, where k\in\mathbb{R}. Then, the following relationships are consequently found:

\alpha_{1} = -2\cdot \alpha_{3}

\alpha_{1} = -2\cdot k

\alpha_{2}= -2\cdot \alpha_{3}

\alpha_{2} = -3\cdot k

It is evident that \alpha_{1} and \alpha_{2} are multiples of \alpha_{3}, which means that the set of vector are linearly dependent.

p_{1}(t) = 1, p_{2}(t)=t^{2} and p_{3}(t) = 3+3\cdot t +t^{2}

\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0

\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2}+ \alpha_{3}\cdot (3+3\cdot t+t^{2}) = 0

(\alpha_{1}+3\cdot \alpha_{3})\cdot 1+(\alpha_{2}+\alpha_{3})\cdot t^{2}+3\cdot \alpha_{3}\cdot t = 0

The following system of linear equations is obtained:

\alpha_{1}+3\cdot \alpha_{3} = 0

\alpha_{2} + \alpha_{3} = 0

3\cdot \alpha_{3} = 0

Whose solution is \alpha_{1} = \alpha_{2} = \alpha_{3} = 0, which means that the set of vectors is linearly independent.

The set of vectors A and C are linearly independent.

4 0
3 years ago
Other questions:
  • Need help solving please.​
    15·1 answer
  • Which points are solutions to the system of inequalities shown below?
    14·1 answer
  • 10 over 20 how to make it a mixed number
    5·2 answers
  • I need help with #36 I don’t understand
    14·2 answers
  • Ok so my homework assignment is this ...(Circle the correct term that makes the sentence true.The (greatest ,least) of the commo
    6·2 answers
  • What is the probability of having 3 children that are all boys?
    5·1 answer
  • What is the area of this trapezoid 5in 4in 3in 2in
    8·1 answer
  • Solve the following equations mentally 1. 5 – x = 8 2. -1 = x – 2 3. -3x = 9 4. -10 = -5x
    10·2 answers
  • Write an equation for the trend line shown
    7·1 answer
  • Help with this exponential function!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!