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natima [27]
3 years ago
12

PLZ HELP ME :(

Mathematics
1 answer:
Lesechka [4]3 years ago
4 0

Answer:

D)$660

Step-by-step explanation:

Add all of them up and you get $658.29 the number in the tens place is 5 and the number on the right is 8 so you round up.

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What is the length of pr​
Eduardwww [97]

Answer:

Kinda need more info there

Step-by-step explanation:

6 0
3 years ago
Answer all questions, your combing like terms. Show ALL of you work! Thank you!!
Elanso [62]

Answer:

1. -12x - 9y - 6

2. -12x + 36

3. -240

4. -2

5. x = -57

6. x = -6

7. x = 48

8. x = 20

9. x = -288

10. n = 8

Step-by-step explanation:

1.

-5x - 13 + 3y - 7x - 12y + 7

-12x - 13 + 3y - 12y +  7

-12x - 6 + 3y - 12y

-12x - 6 - 9y

-12x - 9y - 6

2.

-3(4x - 12)

-3(4x) + (-3)(-12)

-12x + 36

3.

6x - 282

6(7) - 282

42 - 282

-240

4.

6x + 2(y + x)

6(-2) + 2(7 + (-2))

-12 + 2(7 - 2)

-12 + 2(5)

-12 + 10

-2

5.

x - 23 = -80

 + 23    +23

x = -57  

6.

12x = -72

/12     /12

x = -6

7.

x/4 = 12

* 4    * 4

x = 48

8.

3x + 12 = 72

    -  12  - 12

3x = 60

/3     /3

x = 20

9.

x/4 - 8 = -80

     + 8    + 8

x/4 = -72

* 4    * 4

x = -288

10.

-4(1 - 5n) - 8n = 92

-4 + (-4)(-5n) - 8n = 92

-4 + 20n - 8n = 92

-4 + 12n = 92

12n - 4 = 92

     + 4    + 4

12n = 96

/12     /12

n = 8

6 0
3 years ago
The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q
Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

\frac{\sum f}{4}=\frac{100}{4}=25

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF)_{p} = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

     =34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75

The value of first quartile is 34.75.

Q₃ is at the position:

\frac{3\sum f}{4}=\frac{3\times100}{4}=75

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF)_{p} = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

     =44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83

The value of third quartile is 44.83.

Then the inter-quartile range is:

IQR = Q_{3}-Q_{1}

        =44.83-34.75\\=10.08

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}

                                 =\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89

Thus, the probability that a student scored at most 50 on the examination is 0.89.

5 0
3 years ago
Which of the following sets of numbers could represent the three sides of a right triangle?
NARA [144]

Answer:

16,30.34

Step-by-step explanation:

7 0
3 years ago
Alvin is running at a rate of 3 meters per second. The meters he runs, m, in s seconds is given by the equation m=3s. Identify t
dem82 [27]
It is 6 because I got the awnser multiple times
4 0
3 years ago
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