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2 years ago

Divide. Write the quotient in lowest terms. 1 Col What is 1/4 divided by 1 1/8

Mathematics

1 answer:

Alinara [238K]2 years ago

8 0

Answer:

2/9 or 0.222.

Step-by-step explanation:

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I wiol mark you brainliest!!! Use the substitution method to solve the system of equations.

JulsSmile [24]

Answer: b. (6,27)

Step-by-step explanation:

y=5x- 3 x=6<---- put in the equation

y=5(6)-3 <------- mulitply 5 and 6

y=30-3 <---- subtracted

y= 27. <---- y value.

Answer being (6,27)

Hope it helps :)

5 0

3 years ago

if a line passes through the point (-2,3) and has a slope of 1/5, what would be the point-slope form?

Dmitry_Shevchenko [17]

Answer:

y-3=1/5(x+2)

Step-by-step explanation:

y-3=1/5(x--2)

the negatives cancel out making it

y-3=1/5(x+2)

3 0

3 years ago

Can you help me please

juin [17]

I may be wrong but i think the answer is 13.5

6 0

2 years ago

Can someone please help me . first question .

nikdorinn [45]

Answer:

y = -x + 12

Step-by-step explanation:

2x + 2y = 24

divide all by 2

x + y = 12

y = -x + 12

4 0

3 years ago

Given two independent random samples with the following results: n1=8x‾1=186s1=33 n2=7x‾2=171s2=23 Use this data to find the 90%

KonstantinChe [14]

Answer:

The point of estimate for the true difference would be:

$186-171= 15$

And the confidence interval is given by:

$(186-171) -1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= -10.753$

$(186-171) +1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= 40.753$

Step-by-step explanation:

For this case we have the following info given:

$\bar X_1 = 186$ the sample mean for the first sample

$\bar X_2 = 171$ the sample mean for the second sample

$s_1 =33$ the sample deviation for the first sample

$s_2 =23$ the sample deviation for the second sample

$n_1 = 8$ the sample size for the first group

$n_2 = 7$ the sample size for the second group

The confidence interval for the true difference is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

We can find the degrees of freedom are given:

$df = n_1 +n_2 -2 =8+7-2= 13$

The confidence level is given by 90% so then the significance would be $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ we can find the critical value with the degrees of freedom given and we got:

$t_{\alpha/2}= \pm 1.77$

The point of estimate for the true difference would be:

$186-171= 15$

And replacing into the formula for the confidence interval we got:

$(186-171) -1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= -10.753$

$(186-171) +1.77 \sqrt{\frac{33^2}{8} +\frac{23^2}{7}}= 40.753$

5 0

3 years ago