Solution:
1) Rewrite it in the form {a}^{2}-2ab+{b}^{2}, where a={d}^{2} and b=4
{({d}^{2})}^{2}-2({d}^{2})(4)+{4}^{2}
2) Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}
{({d}^{2}-4)}^{2}
3) Rewrite {d}^{2}-4 in the form {a}^{2}-{b}^{2} , where a=d and b=2
{({d}^{2}-{2}^{2})}^{2}
4) Use Difference of Squares: {a}^{2}-{b}^{2}=(a+b)(a-b)
{((d+2)(d-2))}^{2}
5) Use Multiplication Distributive Property: {(xy)}^{a}={x}^{a}{y}^{a}
{(d+2)}^{2}{(d-2)}^{2}
Done!
Answer:
Option A
Step-by-step explanation:
<u>Given equation is</u>
=> 3y = 6x + 3
<u>In slope-intercept form, it becomes</u>
=> 3y = 3(2x+1)
=> y = 2x+1
So, Slope = m = 2
<u><em>Parallel lines have equal slope, So any line parallel to the above line would have its slope equal to 2</em></u>
=> Line parallel to 3y = 6x + 3 is y = 2x + 10
The answer is 10x^4 - 2x^3
Answer:
5 units
Step-by-step explanation:
±√(- 2 - 1)^2 + (- 1 - 3)^2 = ±5 (rej - 5 since distance > 0)
Apply distance formula
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