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liq [111]
3 years ago
5

What are the zeros of (x-2)(x^-9)

Mathematics
1 answer:
Nostrana [21]3 years ago
8 0
I suspect you may have slipped up as you copied the question. Exactly as you wrote it, it has a single zero, at x= 2 .
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What is the completely factored form of d4-8d2+16
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Solution:

1) Rewrite it in the form {a}^{2}-2ab+{b}^{2}, where a={d}^{2} and b=4
{({d}^{2})}^{2}-2({d}^{2})(4)+{4}^{2}

2) Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}
{({d}^{2}-4)}^{2}

3) Rewrite {d}^{2}-4​ in the form {a}^{2}-{b}^{2}​​ , where a=d and b=2
{({d}^{2}-{2}^{2})}^{2}
​​
4) Use Difference of Squares: {a}^{2}-{b}^{2}=(a+b)(a-b)
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5) Use Multiplication Distributive Property: {(xy)}^{a}={x}^{a}{y}^{a}
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8 0
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Answer:

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=> y = 2x+1

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GalinKa [24]

Answer:

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Explanation:

-----

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olga_2 [115]

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Apply distance formula

This is a topic on coordinate geometry. If you would like to find out more you can give my Instagram page a follow as I'll be updating on this topic soon. In addition, I will be posting other useful materials created by myself at the same platform too!

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