Answer:
The proportion of children that have an index of at least 110 is 0.0478.
Step-by-step explanation:
The given distribution has a mean of 90 and a standard deviation of 12.
Therefore mean,
= 90 and standard deviation,
= 12.
It is given to find the proportion of children having an index of at least 110.
We can take the variable to be analysed to be x = 110.
Therefore we have to find p(x < 110), which is left tailed.
Using the formula for z which is p( Z <
) we get p(Z <
= 1.67).
So we have to find p(Z ≥ 1.67) = 1 - p(Z < 1.67)
Using the Z - table we can calculate p(Z < 1.67) = 0.9522.
Therefore p(Z ≥ 1.67) = 1 - 0.9522 = 0.0478
Therefore the proportion of children that have an index of at least 110 is 0.0478
Answer:
x=3
Step-by-step explanation:
The simplified expression is: -14s⁴-2s²+3s-3.
First group all the like terms together.
(-8s⁴)+(-6s⁴)=-14s
-2s
7s+(-4s)=3s
-3
Then put the expression back together, starting with the term that has the largest exponent, then working your way down. You would then get: -14s⁴-2s²+3s-3.
D because your making the shape smaller 2 times
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