Answer:
The correct option is;
ΔCED ~ ΔCAB
Step-by-step explanation:
Given that the translation maps angle ∠D to angle ∠B, we have;
Angle ∠D is congruent to ∠B (Given)
Segment ED is parallel to segment AB (lines having similar angles to a common transversal)
Therefore, ∠A is congruent to ∠E, (Angle on the same side of a transversal to two parallel lines)
∠C is congruent to ∠C reflexive property
Therefore, we have;
∠C ≅ ∠C
∠E ≅ ∠A
∠D ≅ ∠B
Which gives ΔCED is similar to ΔCAB (not ΔCBA)
Answer:
Like this...
Step-by-step explanation:
The best represented graph should look something like this :)
(program used is Desmos)
Answer:
$960
Step-by-step explanation:
1/5= .2
1-0.2= 0.8
1200×0.8= 960