3 years ago

Integral of e^x (sinx +cosx)

Mathematics

1 answer:

disa [49]3 years ago

8 0

integral of e^x (sinx +cosx)= e^x sin x + c

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Travka [436]

Answer:

either the first or second but id go with the second one!

Step-by-step explanation:

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3 years ago

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Write the vector v in the form aiplusbj, given its magnitude left norm Bold v right norm and the angle alpha it makes with the

photoshop1234 [79]

Answer:

$6\sqrt{3}i-6j$

Step-by-step explanation:

Given:

The magnitude, v=12

The angle $\alpha$ it makes with the positive x-axis = $150^0$

Now for a vector (x,y)

$\alpha =tan^{-1}(\frac{y}{x} )$ ; and

$v=\sqrt{x^2+y^2}$

Therefore:

$150 =tan^{-1}(\frac{y}{x} )\\\frac{y}{x} =tan 150\\\frac{y}{x}=-\frac{\sqrt{3} }{3}$

$y=-\frac{x \sqrt{3}}{3}$

Similarly:

$v=\sqrt{x^2+y^2}\\12=\sqrt{x^2+y^2}\\12^2=x^2+y^2\\144=x^2+y^2$

$144=x^2+(-\frac{x \sqrt{3}}{3} )^2\\144=x^2+\frac{3x^2}{9} \\144=\frac{4x^2}{3}\\4x^2=144 X 3=432\\x^2=108\\x=6\sqrt{3}$

Recall that:

$y=-\frac{x \sqrt{3}}{3}\\y=-\frac{6\sqrt{3} \sqrt{3}}{3}=-6$

Therefore: $(x,y)=(6\sqrt{3}, -6)$

The vector in the form ai+bj is therefore:

$6\sqrt{3}i-6j$

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3 years ago

John is expanding these two brackets.

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Answer: Um, the answer is B, and C?

Step-by-step explanation:

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114 stamps he had before

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zimovet [89]

Answer:

10x+15

Step-by-step explanation:

5 x 2x=10x

5x3=15

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