Alright Soldier I need help, Solve for Percent Error, Calculate the percent error if the experimental value of the density of go
ld is 18.7 g/cm^3 and the accepted value is 19.3 g/cm^3
1 answer:
Answer:
Step-by-step explanation:
so the steps to doing this are as follows :
Subtract the accepted value from the experimental value.
Take the absolute value of step 1.
Divide that answer by the accepted value.
Multiply that answer by 100 and add the % symbol to express the answer as a percentage.
|18.7-19.3|/19.3 = 0.031088 * 100% = 3.1%
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Answer: your answer should be HI i hope it helps
Let slant height be s
Height = 38yd. = h
Side = 42yd. = a
S² = h² + (a/2)²
= 38² + 21²
= 1444 + 441
= 1885
S = √1885
S = 43.42yd.
Lateral area = 1/2 × 4a × s
= 2 × 42 × 43.42
= 3646.99
= 3647 yd.²
Answer:
Step-by-step explanation:
12d - 7 = 41
12d = 48
d = 4
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