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3 years ago

Which is greater, - 5¼ or -5⅓

Mathematics

1 answer:

lana [24]3 years ago

7 0

Answer:

-51/4 is greater

Step-by-step explanation:

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25.2 + 800 - 427..43 × 2.4 ÷ 13

Vinil7 [7]

Step-by-step explanation:

25.2 + 800 - 427.43 x 2.4 ÷ 13

825.2 - 1025.832 ÷ 13

200.632 ÷ 13

= 15.44

6 0

3 years ago

5x−3−7x = 15−x What is x?

Schach [20]

Simplify 5x-3-7 to -2x-3
-2x-3=15-x
Add 2x on both sides
−3=15−x+2x
Simplify 15-x+2x to 15+x
−3=15+x
Subtract 15 on both sides
-3-15=x
Simplify -3-15 to -18
-18=x
X=-18

6 0

4 years ago

Read 2 more answers

In a shipment of 20 packages, 7 packages are damaged. The packages are randomly inspected, one at a time, without replacement, u

horsena [70]

Answer:

$\large\boxed{\large\boxed{0.119}}$

Explanation:

You need to find the probability that exactly three of the first 11 inspected packages are damaged and the fourth is damaged too.

1. Start with the first 11 inspected packages:

a) The number of combinations in which 11 packages can be taken from the 20 available packages is given by the combinatory formula:

$C(m,n)=\dfrac{m!}{m!(m-n)!}$

$C(20,11)=\dfrac{20!}{11!\cdot(20-11)!}$

b) The number of combinations in which 3 damaged packages can be chossen from 7 damaged packages is:

$C(7,3)=\dfrac{7!}{3!\cdot(7-3)!}$

c) The number of cominations in which 8 good packages can be choosen from 13 good pacakes is:

$C(13,8)=\dfrac{13!}{8!\cdot(13-8)!}$

d) The number of cominations in which 3 damaged packages and 8 good packages are chosen in the first 11 selections is:

$C(7,3)\times C(13,8)$

e) The probability is the number of favorable outcomes divided by the number of possible outcomes, then that is:

$\dfrac{C(7,3)\times C(13,8)}{C(20,11)}$

Subsituting:

$\dfrac{\dfrac{7!}{3!\cdot(7-3)!}\times \dfrac{13!}{8!\cdot(13-8)!}}{\dfrac{20!}{11!\cdot(20-11)!}}$

$=\dfrac{\dfrac{7!}{3!\cdot 4!}\times \dfrac{13!}{8!\cdot 5!}}{\dfrac{20!}{11!\cdot 9!}}=0.26818885$

2. The 12th package

The probability 12th package is damaged too is 7 - 3 = 4, out of 20 - 11 = 9:

3. Finally

The probability that exactly 12 packages are inspected to find exactly 4 damaged packages is the product of the two calculated probabilities:

$0.26818885\times 4/9=0.119$

6 0

3 years ago

Solve. 4(x - 3 ) + 5x = -48 a. -4 b. 4 c. all real numbers d. 0

lukranit [14]

X would equal 20/3 or c

7 0

3 years ago

A ball will be drawn from a bag containing 20 balls numbered 1 through 20 . If each ball is equally likely to be drawn, what is

lianna [129]

25% or 1/4 because 5 is 25 percent of 20 and if you change 25% into a decimal you get .25 which is equivalent to 1/4

7 0

3 years ago

Read 2 more answers