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olchik [2.2K]
3 years ago
5

Identify the median for the data of Johnny’s test scores: 92, 96, 97, 83, 92, 58, 93, 88, 77, 48, 65, 80, 71

Mathematics
1 answer:
Anastasy [175]3 years ago
4 0

Answer

The median is 83

Step-by-step explanation:

You must put the scores in order to find median.

48, 58, 65, 71, 77, 80, 83, 88, 92, 92, 93, 96, 97

Then you find the number that is in the exact middle of the list.

In this case the median (middle number) is 83

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<img src="https://tex.z-dn.net/?f=%285%5E%7B3%7D%29%5E%7B-3%7D" id="TexFormula1" title="(5^{3})^{-3}" alt="(5^{3})^{-3}" align="
morpeh [17]

<h3>\frac{1}{1953125} ✅</h3>

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

( { {5}^{3} })^{ - 3}  \\   \\ which\:means \:that \: {5}^{3}\:  is \:multiplied \:thrice\: with\: itself\\ \\ =  {5}^{3 \times  - 3}  \\ \\   =  {5}^{ - 9}  \\  \\=  \frac{1}{ {5}^{9} }  \\  \\  =  \frac{1}{5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5 \times 5}  \\   \\ =  \frac{1}{1953125}

<u>Note</u>:-

( { {a}^{m} })^{n}  =  {a}^{m \times n}

{a}^{ - m}  =  \frac{1}{ {a}^{m} }

\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}

4 0
3 years ago
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