Pls i need help on these I HAVE BEEN STUCK
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We have that the workdone in stretching natural length to is mathematically given as
W=9/2lbft
<h3>Workdone in stretching natural length</h3>Question Parameters:
- A force of 128 lb is required to hold a spring stretched 2 ft <em>beyond </em>its natural length.
- Stretching it from its natural length to 9 inches beyond its natural length
Generally the Hookes equation for the Force is mathematically given as
F=Kx
Where
3.2lb=2ft*k
Thereofore
k=16
Force becomes
f=kx
f=16x
Hence
W=9/2lbft
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