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julsineya [31]
3 years ago
8

15. Find the slope of a line perpendicular to 2y=-6x+8 2/3 6 1/3 -3/2

Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0
The slope of the given line is found from the coefficient of x after dividing the equation by 2.
.. y = -3x +4
The given line has slope -3.
A perpendicular line will have a slope that is the negative reciprocal of this:
.. -1/(-3) = 1/3

This corresponds to your 3rd choice.

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3 Quiz
sertanlavr [38]

Answer:

y varies of directly as x. This means that the equation is of the form y=kx where k is any number.

Substituting y=12 when x=4, we get

12=k×4⇒k=3

Hence, the required equation is y=3x.

The value of y when x=5 is y=3x5=15.

Step-by-step explanation:

bro it will work ♥️

5 0
3 years ago
8z-13=7 what's the number that replaces z
Goshia [24]
All you do is solve for z. So 8z-13=7. To solve for a variable you have to do the opposite to cancel out the numbers on each side. First you add 13 over to 7 to cancel out 13 on the z side. So 8z=20 is what you have left. Then you divide 8 on both sides to cancel out 8 on the z side. what you are left with is z=2.5. Lastly you plug and check. 8(2.5) - 13 = 7, 20-13=7. And thats correct so z is 2.5.
4 0
3 years ago
Read 2 more answers
The long-distance calls made by the employees of a company are normally distributed with a mean of 6.3 minutes and a standard de
Sergio [31]

To solve this problem, we use the formula:

z = (x – u) / s

where z is the z score value which can be obtained from the tables, x is the sample value, u is the mean = 6.3 min, and s is the std dev = 2.2 min

 

at P value = 0.90, the z = 1.28, finding for x:

x = z s + u

x = 1.28 * 2.2 + 6.3

x = 9.116

 

at P value = 1.0, the z = 3.49, finding for x:

x = z s + u

x = 3.49 * 2.2 + 6.3

x = 13.978 ~ 14

 

Therefore the longest 10% calls last about 9.1 minutes to 14 minutes

3 0
3 years ago
Given: y" - 2y' = 6t + 5e^2t. Find the correct form to use for y_p if the equation is solved using Undetermined coefficients. Do
const2013 [10]

Answer:

y_p=A+Bt+Ce^{2t}

Step-by-step explanation:

Given: y'' - 2y' = 6t + 5e^{2t}.

we need to find the correct form for y_p if the equation is solve using undetermined coefficients.

A first order differential equation \frac{\mathrm{d} y}{\mathrm{d} x}=f\left ( x,y \right ) is said to be homogeneous if f(tx,ty)=f(x,y) for all t.

Consider homogeneous equation y''-2y'=0

Let y=e^{rt} be the solution .

We get (r^2-2r)e^{rt}=0

Since e^{rt}\neq 0, r^2-2r=0.

So, we get solution as y_c=c_1+c_2e^{2t}

As constant term and e^{2t} are already in the R.H.S of equation

y" - 2y' = 6t + 5e^{2t}, we can take y_p as y_p=A+Bt+Ce^{2t}

6 0
3 years ago
Subtract -7n +2 from 2n - 1
Irina18 [472]
2n - 1    -      -7n + 2     You combine like terms with subtracting
2n - 7n = -5n
-1 - 2 = -3
So -7n + 2     -     2n - 1 = -5n - 3
4 0
3 years ago
Read 2 more answers
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