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3241004551 [841]
2 years ago
8

What is the solution to the system of linear equations?​

Mathematics
1 answer:
Natalija [7]2 years ago
8 0

Answer:

The solution to a system of linear equations is the point at which the lines representing the linear equations intersect. Two lines in the x y xy xy -plane can intersect once, never intersect, or completely overlap.

Step-by-step explanation:

You might be interested in
Help me with my math ASAP!!!!
almond37 [142]

Answer:

f = 78

g = 3.5

Step-by-step explanation:

First we need to find f.

We can use the equation 72 + (f + 30) = 180 to solve for f.

We can then change that equation to 72 + f + 30 = 180, since the Commutative Property of Addition says that you can have any addition in any order.

Now, we can solve the equation.

102 + f = 180\\(102 - 102) + f = 180 - 102\\f = 78

Now that we solved f, we can now solve for g.

Since 25 equals 8g -3, we can solve the equation 8g - 3 = 25.

Here is how you solve it:

8g - 3 = 25\\8g + (-3 + 3) = 25 + 3\\8g = 28\\g = \frac{28}{8}

Since \frac{28}{8} equals 3.5, which is the simplest form, that is the answer.

Hope this helps, and please mark me brainliest! :)

3 0
3 years ago
Write an equation in​ slope-intercept form of the line that passes through the given point and is parallel to the graph of the g
Bumek [7]
Your parallel equation would be y=-3x-32.
5 0
3 years ago
**The following scenario is for #12, #13, and #14 on this test.** A school chorus has 90 sixth grade students and 75 seventh gra
givi [52]

Answer:

The music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.

Step-by-step explanation:

A school chorus has 90 sixth-grade students and 75 seventh-grade students.

Factor these two numbers:

Find GCF(90,75):

Now,

Therefore, the music director can make 15 groups of performers with 6 sixth grade students and 5 seventh grade students in each group.

6 0
2 years ago
If it takes you 40 minutes to go 20 miles downstream and then 60 minutes on the way back, what is the speed of the current?
IrinaK [193]

Answer:

Speed of Current = 5 miles per hour

Step-by-step explanation:

We know distance formula,

D = RT

Where

D is distance

R is rate

T is time

If we let speed of boat (assume) to be "x" and speed of current to be "c"

Then downstream rate is (with current) = x + c

Upstream rate is (against current) = x - c

40 mins to go 20 miles downstream, that means:

D = RT

20 = (x + c)(40)

and

60 minutes to go upstream, 20 miles, that means:

D = RT

20 = (x - c)(60)

Simplifying first equation:

40x + 40c = 20

Simplifying second equation:

60x - 60c = 20

Multiplying first equation by 60, we get:

60 * [40x + 40c = 20] = 2400x + 2400c = 1200

Multiplying second equation by 40, we get:

40 * [60x - 60c = 20] = 2400x - 2400c = 800

Now we add up both these equations:

2400x + 2400c = 1200

2400x - 2400c = 800

----------------------------------

4800x = 2000

x = 2000/4800 = 5/12

We need speed of current, that is "c", so we plug in the value of x into first equation and solve for c:

40x + 40c = 20\\40(\frac{5}{12}) + 40c = 20\\\frac{50}{3}+40c=20\\40c=20-\frac{50}{3}\\40c=\frac{10}{3}\\c=\frac{1}{12}

Speed of Current = 1/12 miles per minute

Since there is 60 minutes in an hours, that would be:

(1/12) * 60 = 5 miles per hour

Speed of Current = 5 miles per hour

3 0
3 years ago
A surveyor, Toby, measures the distance between two landmarks and the point where he stands. He also measured the angles between
vagabundo [1.1K]
What we know so far:
Side 1 = 55m
Side 2 = 65m
Angle 1 = 40°
Angle 2 = 30°

What we are looking for:
Toby's Angle = ?
The distance x = ?

We need to look for Toby's angle so that we can solve for the distance x by assuming that the whole figure is a SAS (Side Angle Side) triangle.

Solving for Toby's Angle:
We know for a fact that the sum of all the angles of a triangle is 180°; therefore,
180° - (Side 1 + Side 2) = Toby's Angle
Toby's Angle  = 180° - (40° + 30°)
Toby's Angle = 110°

Since we already have Toby's angle, we can now solve for the distance x by using the law of cosines r² = p²+ q²<span>− 2pq cos R where r is x, p is Side1, q is Side2, and R is Toby's Angle.
</span>
x² = Side1² + Side2² - 2[(Side1)(Side2)] cos(Toby's Angle)
x² = 55² + 65² - 2[(55)(65)] cos(110°)
x² = 3025 + 4225 -7150[cos(110°)]
x² = 7250 - 2445.44
x = √4804.56
x = 69.31m

∴The distance, x, between two landmarks is 69.31m
8 0
2 years ago
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