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3241004551 [841]
3 years ago
8

What is the solution to the system of linear equations?​

Mathematics
1 answer:
Natalija [7]3 years ago
8 0

Answer:

The solution to a system of linear equations is the point at which the lines representing the linear equations intersect. Two lines in the x y xy xy -plane can intersect once, never intersect, or completely overlap.

Step-by-step explanation:

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Can you help me please now
harkovskaia [24]

26 divided by 2 is 13

13 divided by 2 is 6.5

6.5 + 6.5 = 13


5 0
3 years ago
Scott is on his school's academic team. On average, it takes Scott 4 minutes, with a standard deviation of 0.25 minutes, to solv
uysha [10]

Answer:

15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4 minutes

Standard Deviation, σ = 0.25 minutes

We standardize the given data.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(more than 4.25 minutes to solve a problem)

P( x > 4.25) = P( z > \displaystyle\frac{4.25 - 4}{0.25}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 4.25) = 1 - 0.8413 = 0.1587 = 15.87\%

Thus,15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

8 0
3 years ago
Help please<3
ale4655 [162]
Y=-3/2x+4

The slope is -3/2, since Kerry traveled three feet and only went down 2.

The y intercept is 4, since she started four feet above the origin
3 0
3 years ago
Find an equation of the ellipse that has center (-2,0), a minor axis of length 2, and a vertex at (8,0)
Viefleur [7K]

Answer:

Step-by-step explanation:

(-2,0) and (8,0) are horizontally aligned, so the ellipse is horizontal.

6 0
3 years ago
1.- What type of parabola is this?
xz_007 [3.2K]

Answer:

<u>Part 1</u>

<u>Sideways or "horizontal" parabola</u> with a horizontal axis of symmetry.

<u>Part 2</u>

The vertex is the turning point:  (-3, 1)

<u>Part 3</u>

Vertex form of a horizontal parabola:

x=a(y-k)^2+h    

where:

  • (h, k) is the vertex
  • a is some constant
    If a > 0 the parabola opens to the right.
    If a < 0 the parabola opens to the left.

Point on the curve:  (-1, 2)

Substituting the vertex and the found point into the formula and solving for a:

\implies -1=a(2-1)^2-3

\implies -1=a-3

\implies a=2

<u>Part 4</u>

Equation for the given parabola in vertex form:

x=2(y-1)^2-3

Equation in standard form:

x=2y^2-4y-1

4 0
2 years ago
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