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3241004551 [841]
2 years ago
8

What is the solution to the system of linear equations?​

Mathematics
1 answer:
Natalija [7]2 years ago
8 0

Answer:

The solution to a system of linear equations is the point at which the lines representing the linear equations intersect. Two lines in the x y xy xy -plane can intersect once, never intersect, or completely overlap.

Step-by-step explanation:

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Please help I need help
navik [9.2K]

Answer:

L=10pi, or 31.42

Step-by-step explanation:

4 0
3 years ago
Y = 2x - 4<br> y = - 2x + 8<br> Math
WITCHER [35]

Answer:

(3,2)

Step-by-step explanation:

Since both equations are equal to each others.

2x-4=-2x+8

2x+2x=8+4

4x=12

x=3

Substitute x = 3 in any given equations but I will substitute in the first equation.

y = 2(3)-4

y = 6-4

y = 2

3 0
3 years ago
On the coordinate plane. What is the length of BC if the B coordinate is (1 , 6)
agasfer [191]
You just have to plug your coordinates into the distance formula.
(1, 6) (8, 1)
(X1, Y1) (X2, Y2)

do the work and you get 8.6

4 0
3 years ago
Read 2 more answers
Honors Geometry QUiz- Please Help
viktelen [127]

Answer:

QUESTION 2:

The area of the polygon is 21.5 units²

QUESTION 3:

The area of the combined figure is 12 + 18.25·π units²

QUESTION 4:

The area of the figure is 40 units²

QUESTION 5

The area of the compost shape is 40 in.²

Step-by-step explanation:

QUESTION 2.

The area of the polygon is given as follows;

The area of two triangles + The area of trapezoid

1/2×6×3 + 1/2×3×4 + 1/2×(6 + 7) = 21.5 units²

QUESTION 3

The diameter of the semicircle, 'd', is given as follows;

d = √(8² + 3²) = √73

The area of the semicircle = π·d²/4 = π·73/4 = 18.25·π unit²

The area of the right triangle beside the semicircle is given as follows;

1/2 × 8 × 3 = 12 unit²

The area of the combined figure = The area of the semicircle + The area of the right triangle

∴ The area of the combined figure = 12 + 18.25·π units²

QUESTION 4:

The dimensions of the parallelogram are;

Width, W = √(4² + 1²) = √(17)

Length, L = √(8² + 2²) = √(68)

The area of the parallelogram, A_R = W × L = √(17) × √(68) = √(17 × 68) = 34

The area of the parallelogram, A_R = 34 units²

The length of a parallel side, 'A', of the parallelogram is A = 6

The height of the parallelogram, is h = 1

The area of the parallelogram is A = B·h = 6 × 1 = 6 units²

The area of the figure is the sum of the area of the rectangle and the area of the parallelogram

Therefore, we have;

The area of the figure = 34 units² + 6 units² = 40 units²

QUESTION 5

The composite shape consists of a triangle and a rectangle

Therefore, we have;

The area of the rectangle = 5 in. × 7 in. = 35 in.²

The area of the triangle = 1/2 × 2 in. × 5 in. = 5 in.²

The area of the compost shape = The area of the rectangle + The area of the triangle

∴ The area of the compost shape = 35 in.² + 5 in.² = 40 in.²

The area of the compost shape = 40 in.².

5 0
3 years ago
5/12x-168= ?/12y(x-14)
butalik [34]

Move all terms to the left side and set equal to zero. Then set each factor equal to zero


m=                     5x-2016

                        _______

                         y (x-14)


(I'm trying to draw a fraction lol)


6 0
3 years ago
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