What is the solution to the system of linear equations?
1 answer:
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You just have to plug your coordinates into the distance formula.
(1, 6) (8, 1)
(X1, Y1) (X2, Y2)
do the work and you get 8.6
(1, 6) (8, 1)
(X1, Y1) (X2, Y2)
do the work and you get 8.6
Answer:
QUESTION 2:
The area of the polygon is 21.5 units²
QUESTION 3:
The area of the combined figure is 12 + 18.25·π units²
QUESTION 4:
The area of the figure is 40 units²
QUESTION 5
The area of the compost shape is 40 in.²
Step-by-step explanation:
QUESTION 2.
The area of the polygon is given as follows;
The area of two triangles + The area of trapezoid
1/2×6×3 + 1/2×3×4 + 1/2×(6 + 7) = 21.5 units²
QUESTION 3
The diameter of the semicircle, 'd', is given as follows;
d = √(8² + 3²) = √73
The area of the semicircle = π·d²/4 = π·73/4 = 18.25·π unit²
The area of the right triangle beside the semicircle is given as follows;
1/2 × 8 × 3 = 12 unit²
The area of the combined figure = The area of the semicircle + The area of the right triangle
∴ The area of the combined figure = 12 + 18.25·π units²
QUESTION 4:
The dimensions of the parallelogram are;
Width, W = √(4² + 1²) = √(17)
Length, L = √(8² + 2²) = √(68)
The area of the parallelogram, = W × L = √(17) × √(68) = √(17 × 68) = 34
The area of the parallelogram, = 34 units²
The length of a parallel side, 'A', of the parallelogram is A = 6
The height of the parallelogram, is h = 1
The area of the parallelogram is A = B·h = 6 × 1 = 6 units²
The area of the figure is the sum of the area of the rectangle and the area of the parallelogram
Therefore, we have;
The area of the figure = 34 units² + 6 units² = 40 units²
QUESTION 5
The composite shape consists of a triangle and a rectangle
Therefore, we have;
The area of the rectangle = 5 in. × 7 in. = 35 in.²
The area of the triangle = 1/2 × 2 in. × 5 in. = 5 in.²
The area of the compost shape = The area of the rectangle + The area of the triangle
∴ The area of the compost shape = 35 in.² + 5 in.² = 40 in.²
The area of the compost shape = 40 in.².