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gregori [183]
3 years ago
9

Y=-x+Use the rule y= -x+7 to fill in the blank. If (1,y) is on the graph, then y=

Mathematics
2 answers:
alexandr1967 [171]3 years ago
7 0
Y=6

Reason:
(x,y) -> if 1 is where x is then x=1

-1+7=6
Viefleur [7K]3 years ago
6 0

Answer:

y=6

Step-by-step explanation:

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8 0
3 years ago
1200+0.075x>=3300 what is the solution to the inequality
miskamm [114]
Solving inequalities is just like solving any other Algebraic problem...look to P.E.M.D.A.S. (Parenthesis, Exponents, Division, Addition, Subtraction). So lets take a look at this problem now.

1200 + 0.075x\geq3300


Subtract 1200 from both sides...
0.075x\geq2100

Now divide by 0.075...
x\geq28000


NOTE: If you divide or multiple by a negative number while solving inequalities, you must flip the sign. Ex: You answer would be x\leq28000 if you would've multiplied or divided by a negative.




8 0
3 years ago
Why is f(x)=0 the only odd and even function?
kupik [55]
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6 0
3 years ago
Read 2 more answers
The rate of growth of profit​ (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati
Alecsey [184]

Answer:

The function is  P(x) =  \frac{1}{2} e^{-x^2} +0.016

Step-by-step explanation:

From the question we are told that

    The rate of growth  is  P'(x) =  xe^{x} - x^2

     The total profit is P(2)  =$25,000

      The time taken to make the profit is x =  2 \ years

         

From the question

     P'(x) =  xe^{-x^2}  is the rate of growth

  Now here x represent the time taken

Now the total profit is mathematically represented as

       P(x) =  \int\limits {P'(x)} \,  =   \int\limits {xe^{-x^2}} \,

So using substitution method

   We have that

                      u =  - x^2

                      du =  2xdx

  So  

        p(x) =  \int\limits {\frac{1}{2} e^{-u}} \, du

       p(x) =  {\frac{1}{2} [ e^{-u}} +c ]

       p(x) =  {\frac{1}{2}  e^{-x^2}} + \frac{1}{2} c      recall  u =  - x^2   and  let  \frac{1}{2} c =  Z

       

At  x =  2 years  

     P(x)  =$25,000

So

       Since the profit rate is in million

    P(x)  =$25,000 = \frac{25000}{1000000} =$0.025 millon dollars

So  

       0.025 =  {\frac{1}{2}  e^{-2^2}} + Z  

=>    Z = 0.025 - {\frac{1}{2}  e^{-2^2}}  

       Z = 0.016  

So the profit function becomes

         P(x) =  \frac{1}{2} e^{-x^2} +0.016

     

       

5 0
3 years ago
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