The pool can hold 65.84 ft³ of water
<u>Explanation:</u>
Given:
Shape of pool = octagonal
Base area of the pool = 22 ft²
Depth of the pool = 3 feet
Volume, V = ?
We know:
Area of octagon = 2 ( 1 + √2) a²
22 ft² = 2 ( 1 + √2 ) a²
a² = 
a² = 4.55
a = 2.132 ft
Side length of the octagon is 2.132 ft
We know:
Volume of octagon = 
Therefore, the pool can hold 65.84 ft³ of water
Answer:
2 sqrt(2x-1)
Step-by-step explanation:
f(x) = sqrt( x+9)
g(x) = 8x-13
f(g(x))
place the function g(x) in for x in f(x)
f(g(x)) = sqrt(8x-13+9)
Combine like terms
f(g(x)) = sqrt(8x-4)
Factor out 4
f(g(x)) = sqrt(4*(2x-1)
2 sqrt(2x-1)
Answer:
57 seconds
Step-by-step explanation:
55.7 + 1.3 = 57 seconds
Answer:
x+5
Step-by-step explanation:
When you move to the right or left , that's on the x axis. And since it's to the right, the x- coordinate becomes larger. Hope this helps!
For #2, ∠3 and ∠1 are supplementary. You know that the measure of ∠1 is 162°, so what is ∠3? 180-162=18.
m∠3=18° if ∠1=162°.
Hope this helped!
