Answer: one solution x + 3 = 5 x = 2 no other other value for x is possible
No solution: (x + 3) = 2(x +3)
Infinitely many solutions: x+3 = 3 + x
Step-by-step explanation:
why (x + 3) = 2(x +3) has no solution. Can you solve?
x+3=2x+6 -x=3 x=-3 substute -3 for x
(-3)+ 3)= 2[(-3) +3]
-3+3 = -6 +3
0 = -3 False!
x+3 = 3 + x has infinitely many solutions. Substitute any number for x, and the equation is true (5)+3=3+(5) 8=8 . 11111+3 =3+11111 11114=11114
Answer:
66
Step-by-step explanation:
105+420=525 (Total Money)
7x3.25=22.75 (Cost of all bracelets)
8x11.74=93.92 (Cost of all necklaces)
93.92+22.75=116.67 (Cost of all Christmas presents)
525-116.67=408.33 (Total money - Cost of all Christmas presents)
408.33/6.15=66.39... (Amount of necklaces)
since in real life you can only buy a whole number of things, you would round down 66.39 to 66. I hope this helped!
Answer:
(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy
Step-by-step explanation:
(9xy^2 + 12x^3y^4 − 6x) ÷ 3x = 4x^2y^4 + 3y^2 − 2 (False: 9xy^2:3x=3y^2)
25x^4y^2 + 10x^2y^4 − 15y) ÷ 5y = 5x^4y + 2x^3y^2 − 3 (False: 10x^2y^4:5y=2x^2y^3)
(16x^4y^2 + 24x^2y^2 − 8xy^2) ÷ 4xy = 4x^4y + 6xy− 2y(False: 16x^4y^2:4xy=4x^3y)
(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy (True)
It could be any fraction from 5/9 to 7/9.
