The line 
is already written in the 
form. This means that 
is the slope. If two lines are perpendicular, their slopes are the anti-inverse of each other, i.e. their product is -1.
So, our perpendicular line has a slope of 
Finally, we want a line passing through (1,1) with slope :
Answer:
(x-3), 4 (x - 3)^2 (x + 3) (2 x + 7)
Step-by-step explanation:
Factor all the expressions,
1st expression= 4x^2 - 36=4(x^2-9)=4(x+3)(x-3)
2nd expression=2x^2 - 12x + 18 =2(x^2-6x+9)=2 (x - 3)^2=2(x-3)(x-3)
3rd expression=2x^2 + x - 21=(x - 3) (2 x + 7)
HCF=Commo factor=(x-3)
LCF=Common factor*Remaining factor=4(x+3)(x-3)(x-3) (2 x + 7)=4 (x - 3)^2 (x + 3) (2 x + 7)
Answer:
B is the answer for this question. :)
Step-by-step explanation:
I assume you mean x squared in the first equation
Because both are equal to y, they are equal to each other so x + 5 = x^2 +3
If we then move everything over to one side, we get x^2 - x - 2 = 0
Then factorise it to (x-2)(x+1) = 0
And solve both parts separately
x + 1 = 0
x = -1
x-2 = 0
x = 2
Sub both values into the simplest equation in this case y=x+5
to get y = 4 and y = 7
Answer:
why does it say deleted acct
Step-by-step explanation:
if its deleted why is it still here
