#3 is even I really hope this works
Hello,
Let a the first, b the second and c the third.
a+b+c=53
b=a/3
c=2a
==>a+a/3+2a=53
==>10a/3=53
==>a=15.9
c=2*a=2*15.9=31.8
b=a/3=15.9/3=5.3
Proof: a+b+c=15.9+5.3+31.8=53
The second number is 5.3
Answer:
10 min
Step-by-step explanation:
35/7=5 blocks in 1 min
50/5=10
The area of the triangle PQR is 17.6 square units.
Explanation:
Given that the sides of the triangle are PQ = 12 and PR = 3 and 
We need to determine the area of the triangle PQR
<u>Area of the triangle:</u>
The area of the triangle can be determined using the formula,

Substituting the values, we get,

Simplifying, we have,

Multiplying the terms, we have,

Dividing, we get,

Rounding off to the nearest tenth, we have,

Thus, the area of the triangle PQR is 17.6 square units.
T = 0
=> Q = 0
t = x
=> Q = arcsin(x/a)
rest it just simple integration of trigonometric function