Answer:
In bold.
Step-by-step explanation:
a. (x+5)^2 – 3x(x+5) x+5 is common
= (x + 5)(x + 5 - 3x)
= (x + 5)(5 - 2x)
b. (x + 5)(5 - 2x) = 0
x = -5, 2.5.
2a. Area of the square = (x + 5)^2
Area of triangle AEB
= 1/2 * base * height
I am assuming that H is the centre of AB , so
Area = x*x
= x^2.
2b
6x^2 = (x + 5)^2
6x^2 = x^2 + 10x + 25
5x^2 - 10x - 25 = 0
x^2 - 2x - 5 = 0
x = [-(-2) +/- sqrt(2^2 - 4*1*-5)] / 2
x = -1.45, 3.45.
(we ignore the negative).
Answer: B. 2=3x+10x^2
Step-by-step explanation:
The expression means the quadratic function equation.
B = 10x^2 + 3x -2 = 0
the equation is [-b ±√(b^2 -4ac)]/2a
b should be +3 to become -3 when it is plugged into the equation, and 'a' should be 10, and c should be -2.
The correct answer is: "(-1, -2)" .
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Note: By examining the point of intersection of the lines of the 2 graphs show in the "image attached", we can see that the point of intersection is at: "(-1, 2"); that is: "x = -1, y = 2" .
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Answer:
and 
Step-by-step explanation:
-equation 1
-equation 2
Solving the equation 1 to get the value of
To solve such type of equations that have two unknown variables, find the value of one variable in terms of the other from any one of the equation and put the value in the second equation which will give the value of both the variables
Solving Equation 2 to find x
equation 3
Putting this value of x in the equation 1
,
Putting the value of y in equation 3 to find the value of x
4^3*4^-5= 4^-2 (add the exponents since the base is the same)
5^-4*5^1= 5^-3 (add the exponents since the base is the same)
Square both terms (double the exponents)
(4^-2)^2= 4^-4
(5^-3)2= 5^-6
Then take out negative exponents (x^-a= 1/x^a)
4^-4 /5^-6 = 5^6/4^4
Final answer: 5^6/4^4
If you want it in number form
5^6= 15625
4^4=256
15625/256= 61.035...
