All categories

2 years ago

2. If you drank two 12-ounce cans of soda each day for a year, how much money would you have spent?

Mathematics

1 answer:

alexgriva [62]2 years ago

8 0

Answer:

803 SORRY FOR ALL THE WRONG ANSWERS LOL

Step-by-step explanation:

you multiply the cents and the money by 2 then multiply it by 365

You might be interested in

-3(v+3)-4(v+2) simplify

sergey [27]

Answer:

-7v - 17

Step-by-step explanation:

-3(v+3)-4(v+2)

= -3v - 9 - 4v - 8

= -7v - 17

7 0

3 years ago

Sally wonders if all powders dissolve in water. She decides to see what happens with flour, cornstarch, powdered sugar, and baby

love history [14]

I dot have idea what is this my g sorry

4 0

3 years ago

Read 2 more answers

A deck of cards contains red cards numbered 1,2,3,4,5, blue cards numbered 1,2 and green cards numbered 1,2,3,4,5,6. If a single

tekilochka [14]

Answer:

the probability is 38,46%

Step-by-step explanation:

If all decks are put together and shuffled , then card is picked at random regardless of the number, then the probability that the card is red is

probability = number of red cards / total number of cards = 5/(5+2+6) = 5/13=0.3846= 38,46%

5 0

2 years ago

4. Find the value of x in the equation 9 − 4x = 57. A. 16.5 B. −16.5 C. −12 D. 12

guajiro [1.7K]

Answer:

C. −12

Step-by-step explanation:

9 − 4x = 57

Subtract 9 from each side

9-9-4x= 57-9

-4x = 48

Divide by -4 on each side

-4x/-4 = 48/-4

x = -12

5 0

3 years ago

Lim 1 - cos 40<br>x>01 - cos 60

Nuetrik [128]

Answer:

The answer is 4/9 if the problem is:

$\lim_{\theta \rightarrow 0}\frac{1-\cos(4\theta)}{1-\cos(6\theta)}$ .

Step-by-step explanation:

I think this says:

$\lim_{\theta \rightarrow 0}\frac{1-\cos(4\theta)}{1-\cos(6\theta)}$ .

Please correct me if I'm wrong about the problem.

Here are some useful limits we might use:

$\lim_{u \rightarrow 0}\frac{\sin(u)}{u}=1$

$\limg_{u \rightarrow 0}\frac{\cos(u)-1}{u}=0$

So for our limit... I'm going to multiply top and bottom by the conjugate of the bottom; that is I'm going to multiply top and bottom by $1+\cos(6\theta)$ :

$\lim_{\theta \rightarrow 0}\frac{1-\cos(4\theta)}{1-\cos(6\theta)}\cdot\frac{1+\cos(6\theta)}{1+\cos(6\theta)}$

When you multiply conjugates you only have to do first and last of FOIL:

$\lim_{\theta \rightarrow 0}\frac{(1-\cos(4\theta))(1+\cos(6\theta))}{1-\cos^2(6\theta)}$

By the Pythagorean Identities, the denominator is equal to $\sin^2(6\theta)$ :

$\lim_{\theta \rightarrow 0}\frac{(1-\cos(4\theta))(1+\cos(6\theta))}{\sin^2(6\theta)}$

I'm going to divide top and bottom by $36\theta^2$ in hopes to use the useful limits I mentioned:

$\lim_{\theta \rightarrow 0}\frac{\frac{(1-\cos(4\theta))(1+\cos(6\theta))}{36\theta^2}}{\frac{\sin^2(6\theta)}{36\theta^2}}$

Let's tweak our useful limits I mentioned so it is more clear what I'm going to do in the following steps:

$\lim_{\theta \rightarrow 0}\frac{\sin(6\theta)}{6\theta}=1$

$\lim_{\theta \rightarrow 0}\frac{\cos(4\theta)-1}{4\theta}=0$

The bottom goes to 1. The limit will go to whatever the top equals if the top limit exists.

So let's look at the top in hopes it goes to a number:

$\lim_{\theta \rightarrow 0}\frac{1-\cos(4\theta)}{36\theta^2} \cdot (1+\cos(6\theta)}$

We are going to multiple the first factor by the conjugate of the top; that is we are multiply top and bottom by $1+\cos(4\theta)$ :

$\lim_{\theta \rightarrow 0}\frac{1-\cos(4\theta)}{36\theta^2} \cdot \frac{1+\cos(4\theta)}{1+\cos(4\theta)} \cdot (1+\cos(6\theta)}$

Recall the thing I said about multiplying conjugates:

$\lim_{\theta \rightarrow 0}\frac{1-\cos^2(4\theta)}{36\theta^2} \cdot \frac{1+\cos(6\theta)}{1+\cos(4\theta)}$

We are going to apply the Pythagorean Identities here:

$\lim_{\theta \rightarrow 0}\frac{\sin^2(4\theta)}{36\theta^2} \cdot \frac{1+\cos(6\theta)}{1+\cos(4\theta)}$

$\lim_{\theta \rightarrow 0}\frac{\sin^2(4\theta)}{\frac{9}{4}(4\theta)^2} \cdot \frac{1+\cos(6\theta)}{1+\cos(4\theta)}$

$\lim_{\theta \rightarrow 0}\frac{4}{9}\frac{\sin^2(4\theta)}{(4\theta)^2} \cdot \frac{1+\cos(6\theta)}{1+\cos(4\theta)}$

Ok this looks good, we are going to apply the useful limits I mentioned along with substitution to find the remaining limits:

$\frac{4}{9}(1)^2 \frac{1+\cos(6(0))}{1+\cos(4(0))}$

$\frac{4}{9}(1)\frac{1+1}{1+1}$

$\frac{4}{9}(1)\frac{2}{2}$

$\frac{4}{9}(1)$

$\frac{4}{9}$

The limit is 4/9.

8 0

2 years ago

2. If you drank two 12-ounce cans of soda each day for a year, how much money would you have spent?​

2. If you drank two 12-ounce cans of soda each day for a year, how much money would you have spent?