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What are the domain and range and asympote of h(x)=6^x -4?
2 answers:
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Solving of the system equation: 2x-y=-13 ⇒(1) and y=x+9 ⇒(2)
by substituting from (2) at (1)
2x-(x+9)=-13
2x-x-9=-13
x=-4 ⇒ substituting at (2) ∴ y = -4+9 = 5
The point that represents the solution to the system = (-4,5)
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solving of the system equation: 3x+2y=10 ⇒(1) and 6x-y=10 ⇒(2)
by multiplying equation (2) ⇒ 12x-2y=20 ⇒(3)
adding (1) and (3)
15 x = 30 ⇒ x=2
from equation (2) 6x-y =10 ⇒⇒⇒ y = 6x-10 =12-10=2
The point that represents the solution to the system = (2,2)
=======================================================
solving of the system equation: 4x-3y=5 ⇒(1) and 3x+2y=-9 ⇒(2)
solve for x, y
we find x=-1 and y=-3
The point that represents the solution to the system = (-1,-3)
=======================================================
solving of the system equation: x+y=7 ⇒(1) and x-y=-1 ⇒(2)
adding (1) and (2)
2x=6 ⇒⇒⇒ x = 3
substitute at (1)
y =7-x=7-3=4
The point that represents the solution to the system = (3,4)
=======================================================
solving of the system equation: y=3x-7 ⇒(1) and y=2x-5 ⇒(2)
equating (1) and (2)
solve for x and y
we find x=2 ⇒⇒⇒ y = -1
The point that represents the solution to the system = (2,-1)
=======================================================
The system equation : y = 6 and x =-5
The point that represents the solution to the system = (-5,6)
=======================================================
The attached figure represent a conclusion for the answer
by substituting from (2) at (1)
2x-(x+9)=-13
2x-x-9=-13
x=-4 ⇒ substituting at (2) ∴ y = -4+9 = 5
The point that represents the solution to the system = (-4,5)
========================================================
solving of the system equation: 3x+2y=10 ⇒(1) and 6x-y=10 ⇒(2)
by multiplying equation (2) ⇒ 12x-2y=20 ⇒(3)
adding (1) and (3)
15 x = 30 ⇒ x=2
from equation (2) 6x-y =10 ⇒⇒⇒ y = 6x-10 =12-10=2
The point that represents the solution to the system = (2,2)
=======================================================
solving of the system equation: 4x-3y=5 ⇒(1) and 3x+2y=-9 ⇒(2)
solve for x, y
we find x=-1 and y=-3
The point that represents the solution to the system = (-1,-3)
=======================================================
solving of the system equation: x+y=7 ⇒(1) and x-y=-1 ⇒(2)
adding (1) and (2)
2x=6 ⇒⇒⇒ x = 3
substitute at (1)
y =7-x=7-3=4
The point that represents the solution to the system = (3,4)
=======================================================
solving of the system equation: y=3x-7 ⇒(1) and y=2x-5 ⇒(2)
equating (1) and (2)
solve for x and y
we find x=2 ⇒⇒⇒ y = -1
The point that represents the solution to the system = (2,-1)
=======================================================
The system equation : y = 6 and x =-5
The point that represents the solution to the system = (-5,6)
=======================================================
The attached figure represent a conclusion for the answer