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adelina 88 [10]
3 years ago
11

What are the domain and range and asympote of h(x)=6^x -4?

Mathematics
2 answers:
jeka943 years ago
3 0

Answer:

Domain: (-oo, oo)

Range: (-4,oo)

Horizontal asymptote: y=-4

Vladimir [108]3 years ago
3 0

Answer:

The domain is all Real numbers.

The range is all real values > -4.

Step-by-step explanation:

The asymptote is y = -4.

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I need help with numbers 1-4 please if someone could help me
laila [671]
You can use the slope formula or just calculate
\frac{rise}{run}
So for the first problem you run 3 units right and rise 5 units so
\frac{rise}{run}  =  \frac{5}{3}
2. Notice the y axis goes by 2 units.
\frac{ - 10}{4}  =  \frac{ - 5}{4}
3.
\frac{0}{12}  = 0
4.
\frac{2}{0}  = undefined
Please let me know if you have questions
3 0
3 years ago
A=?<br><br> b=?<br><br> C =?<br><br> Can someone tell me the answer please
beks73 [17]

Answer:

Below.

Step-by-step explanation:

a = 37 degrees ( vertical angle to 37 )

c = 180 - 37 = 143 degrees (adjacent angles add up to 180).

b = 180 - 37 - 109 = 34 degrees   (angles in a triangle sum to 180 degrees).

5 0
2 years ago
Read 2 more answers
Factor completely x2 + 20x + 99​
Bad White [126]

x^2 + 20x + 99=x^2+9x+11x+99=x(x+9)+11(x+9)=(x+11)(x+9)

6 0
2 years ago
Can someone help me
Lemur [1.5K]
Multiplying fractions is just multiplying the numerators together and the denominators together.

\sf\dfrac{4}{7}\times\dfrac{1}{4}\rightarrow\dfrac{4\times 1}{7\times 4}\rightarrow\dfrac{4}{28}\rightarrow\dfrac{1}{7}

\sf\dfrac{4}{7}\times\dfrac{1}{6}\rightarrow\dfrac{4\times 1}{7\times 6}\rightarrow\dfrac{4}{42}\rightarrow\dfrac{2}{21}

To find out which one is bigger, we need a common denominator. The LCM of 7 and 21 is 21, so convert the first fraction into a denominator of 21. 7 goes into 21 three times, multiply this to the numerator and denominator:

\sf\dfrac{1}{7}\rightarrow\dfrac{1\times 3}{7 \times 3}\rightarrow\dfrac{3}{21}

Now just compare the numerators to see which one is bigger.

\sf\dfrac{3}{21}>\dfrac{2}{21} therefore, \sf\dfrac{4}{7}\times\dfrac{1}{4}>\dfrac{4}{7}\times\dfrac{1}{6}
5 0
3 years ago
The monthly cost of a short term disability insurance policy varies directly as the salary of the employee. Wanda has an annual
arlik [135]

Answer: $14.85

Step-by-step explanation:

Ww can solve the question using direct proportion with the formula y = kx

where y = annual salary

x = monthly policy cost.

k = constant of proportionality

Since y = kx

38500 = 11.55k

k = 38500 / 11.55

k = $3333.33

When Randy has an annual salary of $49,500, the amount Randy expect to pay for his policy will be:

y = kx

49500 = 3333.33x

x = 49500 / 3333.33

x = 14.85

The amount that Randy expect to pay for his policy will be $14.85

8 0
2 years ago
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