Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
Answer:
5/9
Step-by-step explanation:
Answer:
Step-by-step explanation:
The discriminant tells you where the graph of the parabola goes through the x-axis, if at all. If the discriminant is negative there are no real zeros and the parabola does not cross or touch the x-axis; if the discriminant is positive the parabola will go through the x axis in 2 places; if the discriminant is 0 the parabola will touch the x-axis in 1 place. Our discriminant is 0 since the parabola only touches the x-axis but does not go through.
Answer:
radius is 5 because of the center of the origin
Answer: 32w
Step-by-step explanation:
