Set equal to eachother
(2x+1) = 79
Subtract 1 from both sides
2x=78
Divide 2 from both sides
2x/2=78/2
X= 39
Number of tickets: T.
Number of customers: c
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150
For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)
Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150
Answer:
112
Step-by-step explanation:
Just solve it easy peasy
![7[(25+9)-3(2-1)]](https://tex.z-dn.net/?f=7%5B%2825%2B9%29-3%282-1%29%5D)
First solve the inner brackets
![7[(34)-3(3)]\\7[25-9]](https://tex.z-dn.net/?f=7%5B%2834%29-3%283%29%5D%5C%5C7%5B25-9%5D)
Now the other brackets
![7[25-9]\\7[16]\\112](https://tex.z-dn.net/?f=7%5B25-9%5D%5C%5C7%5B16%5D%5C%5C112)
Answer:
A
Step-by-step explanation:
i looked at my chart
