$400.72 - This is how it’s done.
Answer:
x=−63
Step-by-step explanation:
Solve for xx by simplifying both sides of the equation, then isolating the variable.
Conditional probability is the probability that an event is occurring while another has occured. Mathematically, we can compute for the conditional probability, P(A|B) as

where P(A∩B) is the probability that events A AND B are occurring at the same time and P(A) is the probability for A to happen.
For our case, given that 50% of the bags contain red, 25% contain pink, and 15% contains red & pink. Thus, we have
P(R) = 0.50
P(P) = 0.25
P(R∩P) = 0.15
So, the conditional probability of the events below to happen can be calculated as shown.
1. <span>conditional probability that a bag of pink candy also contains red candy is
</span>

2. conditional probability that a bag of red candy also contains pink candy is

From this, we see that the conditional probability that a bag of red candy also contains pink candy is greater.