Answer:
Step-by-step explanation:
1. Answer below
![2x = \sqrt[3]{125}](https://tex.z-dn.net/?f=2x%20%3D%20%5Csqrt%5B3%5D%7B125%7D)



2. Answer below
![x + 3^{2} = \sqrt[3]{27}](https://tex.z-dn.net/?f=x%20%2B%203%5E%7B2%7D%20%3D%20%5Csqrt%5B3%5D%7B27%7D)


Answer:
0.815
Step-by-step explanation:
First, find the z-scores.
z = (x − μ) / σ
z₁ = (8 − 10) / 1
z₁ = -2
z₂ = (11 − 10) / 1
z₂ = 1
P(-2 < Z < 1) = P(Z < 1) − P(Z < -2)
Use a chart, calculator, or the empirical rule to find the probability.
Using the empirical rule:
P(-2 < Z < 1) = 0.84 − 0.025
P(-2 < Z < 1) = 0.815
Using a chart:
P(-2 < Z < 1) = 0.8413 − 0.0228
P(-2 < Z < 1) = 0.8185
Answer:
3 liters.
Step-by-step explanation:
You can write the problem as an equation.
f(x)=0.125x
Where x is the number of hours. The 0.125 is how many liters the faucet loses in 1 hour. Then, just plug in 24.
0.125*24=3
Answer:
345
Step-by-step explanation:
We can solve this problem by two equations. Our variables will be the following:
is the amount to be multiplied
and
is the amount that should be obtained by multiplying by 43
Thus our <u>first equation</u> is:

But the problem tells us that there was an error and the number
was multiplied by 34, so the result failed by 3105, thus the <u>second equation</u> is as follows:

By multiplying the quantity by 34, an amount is obtained that differs from 3105 from what it would have been obtained if multiplied by 43.
Now we are going to <u>replace the first equation in the second one </u>(
):

And clear to find x:

The number that jimmy was supposed to multiply by 43 is 345.
Hello!
Divide the total amount of chocolates by the number of chcolates each box will contain.
234 ÷ 11 = 21.2727272727
It is a repeating decimal. Now, obviously there won't be 21.2727272727 boxes chcolates.
11 × 21 = 231
11 × 22 = 242
If you multiply 11 by 21, you get 231 -- which is 3 less than the total amount of chocolates. But if you multiply it by 22, you get a number that is greater than 234, so it is not possible.
ANSWER:
There will be 21 boxes of chocolates, and 3 left over.