I just want to know if I’m right
2 answers:
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Answer:
i. ΔAXC ~ ΔCXB
ii. ΔBCX Is-congruent-to ΔACX
Step-by-step explanation:
From the given ΔABC, CX is the altitude of ΔABC; and also an angle bisector of <ACB.
So that:
m<AXC = m<BXC (right angle property)
m<ACX = m<BCX (congruent property)
m<ACX + m<AXC + m<CAX = (sum of angles in a triangle)
m<BCX + m<BXC + m<CBX = (sum of angles in a triangle)
Therefore, from the figure it can be deduced that;
i. ΔAXC ~ ΔCXB (Angle-Angle-Side, AAS, property)
ii. ΔBCX Is-congruent-to ΔACX (Angle-Angle-Side, AAS, property)
Answer:
The answer in the procedure
Step-by-step explanation:
Let
A1 ------> the area of the first square painting
A2 ----> the area of the second square painting
D -----> the difference of the areas
we have
case 1) The area of the second square painting is greater than the area of the first square painting
The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting
D=A2-A1
case 2) The area of the first square painting is greater than the area of the second square painting
The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting
D=A1-A2