Question

Let f(x)= x2 - 14 and g(x) = 6-X. Find (fq)(7).

Answer 1

Answer:

$(fg)(7) = - 35$

Step-by-step explanation:

The given functions are:

$f(x) = {x}^{2} - 14$

and

$g(x) = 6 - x$

We want to to find

$(fg)(7)$

Note that:

$(fg)(x) = f(x) \times g(x)$

We substitute the functions to obtain:

$(fg)(x) = ( {x}^{2} -1 4 ) \times (6 - x)$

We now substitute x=7, to get:

$(fg)(7) = ( {7}^{2} -1 4 ) \times (6 - 7)$

This implies that

$(fg)(7) =( 49-1 4 ) \times (6 - 7)$

$(fg)(7) = 35 \times - 1 = - 35$