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olasank [31]
3 years ago
15

What are the missing angles

Mathematics
1 answer:
stepan [7]3 years ago
7 0

Missing sides or angles??

If it's missing sides... Then using sine rule

A/ sin A = B/ sin B

Let sin A =30° and A=8

Let sin B=60° and B =?

Hence 8/sin 30°=B/sin 60°

Multiplying 8 x sin 60 =B sin 60

6.928 = 0. 5B

Dividing both sides by 0.5

Hence B= 13.856

doing same for side c

Let sin A =30° and A =8

Let sin c =90° and C =?

Hence 8/sin30° = C/sin 90

Sin 90° x8 =. 0.5c

Sin 90=1

1x8 =0.5c

Dividing both sides by 0.5 gives 16

Hence C=16

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13/15 + 1/8 =<br><br> Please help
kogti [31]
Reduce the fraction using 3
13/15+1/8

13/15=1/5

1/5+1/8

8+5/40

fraction response: 13/40
answer in decimal numbers: 0.325




3 0
3 years ago
Read 2 more answers
The perimeter of a rectangle is 30.8 km and it’s diagonal length is 11 km. Find it’s length and width
blsea [12.9K]

Answer:

Length of the rectangle is 15.0325 km and width is 0.3765 km.

Explanation:

Given:

Perimeter of a rectangle = 30.8 km

Length of diagonal of rectangle = 11 km

To find:

The length and width of rectangle=?

Solution:

Lets assume length of the rectangle = x km

And assume width of the rectangle = y km

Lets first create equation using given  perimeter

perimeter of rectangle = 2 ( length +  width )

=> 30.8 km = 2 ( x + y )  

=>x + y = \frac{30.8}{2}

=> y = 15.4 – x             ------(1)

As diagonal and two sides of rectangle forms right angle triangle whose hypoteneus is diagonal ,  

=> length^2 + width^2 = diagonal^2

=> x^2 + y^2 = 11^2

=> x^2 + y^2 = 121

On substituting value of y from (1) in above equation we get

=> x^2 + (15.4-x)^2 = 121

=>x^2 + (15.4)^2 + x^2 – 2 x 15.4 \times x   = 121

=> 2x^2-30.8x + 237.16 -121  = 0

=> 2x^2-30.8x + 116.16 = 0

Solving above quadratic equation using quadratic formula

General form of quadratic equation is  

ax^2 +bx +c = 0

And quadratic formula for getting roots of quadratic equation is  

x= \frac{ -b\pm\sqrt{(b^2-4ac)}}{2a}

As equation is 2x^2-30.8x + 116.16 = 0, in our case

a = 2 ,  b = -30.8 and c = 116.16

Calculating roots of the equation we get

x=\frac{ -(-30.8)\pm\sqrt{(-30.8)^2-4(2)( 11)} } {(2\times2)}

x=\frac{30.8\pm\sqrt{(948.64-88)}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{30.8\pm\sqrt{860.64}}{4}

x=\frac{(30.8\pm29.33)}4

x=\frac{(30.8+29.33)}{4}

x=\frac{(30.8-29.33)}{4}

=> x = 15.0325 or x = 0.3675

As generally length is longer one ,  

So x = 1.0325

From equation (1) y = 15.4 – x = 0.3765

Hence length of the rectangle is 15.0325 km and width is 0.3765 km.

6 0
3 years ago
What is x + 9≤10 as an inequalite ?
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X is less then or equal to 1<u /><em /><u />
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217 is what percent of 620
Flura [38]
\sf  \dfrac{217}{620}  \\  \\ = 0.35 \\  \\ Convert \ the \ decimal \ percent \ by \ multiplying \ 100 \\  \\  0.35 \times 100  \\  \\ = 35\%
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3 years ago
The perimeter of an isosceles triangle is 15.6m. Find the lengths of its sides, if: The base is 3m smaller than a leg ____m, ___
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Leg 1 is 15.6 meters. 15.6-3 is 12.6. And the last leg is 15.6
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