I apologize , but I still don’t get none of these questions , can I have help ?
1 answer:
Answer:
The measures of the angles: m∠1 = 51°, m∠2 = 39°
Step-by-step explanation:
<em>In this type of question, you should substitute the measures of the angle by the given values and solve the equation to find x, then find the measure of each angle.</em>
∵ m∠1 + m∠2 = 90°
∵ m∠1 = 3x°
∵ m∠2 = (x + 22)°
→ Substitute m∠1 by 3x° and m∠2 by (x + 22)° in the equation above
∴ 3x° + (x + 22)° = 90°
→ Add the like terms in the right side
∴ (3x + x) + 22 = 90
∴ 4x + 22 = 90
→ Subtract 22 from both sides
∴ 4x + 22 - 22 = 90 - 22
∴ 4x = 68
→ Divide both sides by 4 to find the value of x
∴
∴ x = 17
→ Now substitute the value of x in each angle to find them
∵ m∠1 = 3x°
∴ m∠1 = 3(17) = 51°
∵ m∠2 = (x + 22)°
∴ m∠2 = (17 + 22) = 39°
The measures of the angles: m∠1 = 51°, m∠2 = 39°
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Values of a polynomial P(x).
To find:
The remainder when P(x) is divided by (x+5).
The remainder when P(x) is divided by (x-3).
Solution:
If a polynomial P(x) is divided by (x-a), then the remainder is P(a).
If the polynomial P(x) is divided by (x+5), then the remainder is P(-5).
Therefore, the remainder is -2 when P(x) is divided by (x+5).
If the polynomial P(x) is divided by (x-3), then the remainder is P(3).
Therefore, the remainder is 7 when P(x) is divided by (x-3).
Here's a rule that applies to this expression:
- Dividing exponents of the same base:
For this, just divide:
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