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3 years ago

6

A circle has a sector with area 24/5pi and central angle of 48°. What is the area of the circle? Either enter an exact answer in

terms of
or use 3.14 for
and enter your answer as a decimal.

1 answer:

ra1l [238]3 years ago

5 0

Answer:

Area_circle = pi*(24/5)*(360/48)=36pi = 113.097

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The coefficient would be c I believe I may be wrong

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200 students in a high school senior class are surveyed about what majors they intend to declare in college.

vekshin1

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2/5

1/2

3/20

3/4

Step-by-step explanation:

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3 years ago

Which numbers are composite numbers? Select all that are true

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3 years ago

Read 2 more answers

IGIVEEEEEEEEEEEEEEEEE BRAINLILSTTT

Temka [501]

Answer:

first box (x): 10

second box (y): 12

Step-by-step explanation:

HIJ is a translation of HIJ

translation just means you move the whole thing without any rotations dialations ect just moving it

from the blue shape it is asking what do you have to do to the x and y to get to the purple shape

you have to go +_x and take away _y

when you add a digit to x it moves to the right

when you add a digit to y it goes one up

because the HIJ are equaly spaced it dosnt matter which one we choose cause it will have the same answer

im going to use J

on the blue J you can see the x value is -8

the purple J's value is 5

to get from -5 to 5 you add 10

-5+5=0

0+5=5

5+5=10

therefore the first box (x) is 10

same thing for the y value im going to use J again

blue y value of J is 7

purple y value of J is -5

their distance is 12

7-7=0

0-5=-5

7+5=12

second box (y) is 12

i hope this helps

8 0

2 years ago

Rockwell hardness of pins of a certain type is known to have a mean value of 50 and a standard deviation of 1.2.a. If the distri

zalisa [80]

Answer:

a

$P(\= X \ge 51 ) =0.0062$

b

$P(\= X \ge 51 ) = 0$

Step-by-step explanation:

From the question we are told that

The mean value is $\mu = 50$

The standard deviation is $\sigma = 1.2$

Considering question a

The sample size is n = 9

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{9} }$

=> $\sigma_x = 0.4$

Generally the probability that the sample mean hardness for a random sample of 9 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_{x}} \ge \frac{51 - 50 }{0.4 } )$

$\frac{\= X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ \= X )$

$P(\= X \ge 51 ) = P( Z \ge 2.5 )$

=> $P(\= X \ge 51 ) =1- P( Z < 2.5 )$

From the z table the area under the normal curve to the left corresponding to 2.5 is

$P( Z < 2.5 ) = 0.99379$

=> $P(\= X \ge 51 ) =1-0.99379$

=> $P(\= X \ge 51 ) =0.0062$

Considering question b

The sample size is n = 40

Generally the standard error of the mean is mathematically represented as

$\sigma_x = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_x = \frac{ 1.2 }{\sqrt{40} }$

=> $\sigma_x = 0.1897$

Generally the (approximate) probability that the sample mean hardness for a random sample of 40 pins is at least 51 is mathematically represented as

$P(\= X \ge 51 ) = P( \frac{\= X - \mu }{\sigma_x} \ge \frac{51 - 50 }{0.1897 } )$

=> $P(\= X \ge 51 ) = P(Z \ge 5.2715 )$

=> $P(\= X \ge 51 ) = 1- P(Z < 5.2715 )$

From the z table the area under the normal curve to the left corresponding to 5.2715 and

=> $P(Z < 5.2715 ) = 1$

So

$P(\= X \ge 51 ) = 1- 1$

=> $P(\= X \ge 51 ) = 0$

5 0

2 years ago