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3 years ago

Match the vocabulary to the proper definition.

Mathematics

2 answers:

zalisa [80]3 years ago

5 0

Answer: again like last time us google. it is really helpful

Step-by-step explanation: open a tab go to google input word you don't know. lookup and wham bam thank you, mam.

That easy ;)

plus you will learn something from it. hope it helps

sry if I sound mean <3

12345 [234]3 years ago

4 0

Answer:

thats not drip

Step-by-step explanation:

thats sweat

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HELP IM CONFUSED PLS PLS WINNER GETS 8 POINTS

MrRa [10]

(10x4x5)+(5x5x5) because you could make 2 shapes out of it. one being a cude that is 5x5x5 and the other being a rectangle that is 4x10x5 thenyou would just add them together. :) hope that helps

3 0

3 years ago

The two-way table shows the number of people whose hobbies are reading or solving puzzles and who either ride a motorcycle or do

enot [183]

The number of people whose hobby is reading but not riding a motorcycle is 5.

<h3>What is the relative frequency of not riding a motorcycle?</h3>

We want to calculate the number of people whose hobby is reading but they don't like riding the motorcycle,

therefore, when we look into the table we will find out that block A2 is the block that represents the number of people whose hobby is reading but not riding a motorcycle.

Hence, the number of people whose hobby is reading but not riding a motorcycle is 5.

Learn more about Relative frequency:

brainly.com/question/14610326

7 0

2 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago

A baseball team has $1,400 to buy baseball uniforms. Each uniform costs $124. Does the team have enough money to buy 11 baseball

seraphim [82]

The uniforms will cost 1,360, so yes they have enough money to buy 11 uniforms.
Hope this helps.

4 0

3 years ago

Read 2 more answers

6 bags of plaster do 33m2 how many m2 can be done with 5 bags

pav-90 [236]

<span>6 bags of plaster do 33m2
5 bags .........................?

33 * 5 / 6 = 27.5

answer: 27.5</span><span>m2</span>

8 0

3 years ago