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2 years ago

How can I solve for c

Mathematics

2 answers:

s2008m [1.1K]2 years ago

8 0

Answer:

$(\frac{2}{5})c$

zzz [600]2 years ago

4 0

Answer:2/5c

Step-by-step explanation:

(a+b)/(a-b) =c

(a-b)/(a+b)=1/c

Multiply both sides by 2/5

2/5 x (a-b)/(a+b)=2/5 x 1/c

2(a-b)/5(a+b)=2/5c

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Which describes the slope of this line?

Mice21 [21]

Positive Slope

TIP for finding what slope it is:

Positive - the line is pointing right

Negative - the line is pointing left

Undefined - the line is pointing up and down

Zero - the line is point from left to right

4 0

2 years ago

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What does d/dx (-8x - 643)=

poizon [28]

See the attachment.....

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2 years ago

A tangent line and its normal line have a point of tangency to the function f(x) at (x,y). If the slop of the normal line is m=(

alekssr [168]

Answer:

$\displaystyle \\\left(\frac{49}{900},\frac{3761}{900}\right)$ or approximately (0.544, 4.179)

Step-by-step explanation:

A function and its tangent lines intersect when their slopes are the same. Find the x-coordinate when the slope of f(x) is equal to 8/7 by taking the derivative of f(x):

$\displaystyle\\f(x)=\sqrt{x}-x+4\\f'(x)=\frac{1}{2}\cdot\frac{1}{\sqrt{x}}-1=\frac{1}{2\sqrt{x}}-1$

Set $f'(x)$ equal to 8/7 and solve for x:

$\displaystyle \\\frac{1}{2\sqrt{x}}-1=\frac{8}{7},\\x=\frac{49}{900}$

Therefore, $f(x)$ will intersect at a point of tangency with a line of slope 8/7 at x=49/900. Plug in x=49/900 into $f(x)$ to get the y-coordinate:

$\displaystyle\\y=\sqrt{x}-x+4 \vert_{x=49/900}=\frac{3761}{900}$

⇒Answer: (49/900, 3761/900) or approximately (0.544, 4.179)

5 0

2 years ago

The radius of a circle is 9 inches. What is the circle's area? Use 3.14 for .

Anna007 [38]

Answer:

254.34 in²

Step-by-step explanation:

Area of a circle

A = πr²

r = radius of the circle

Solving

A = 3.14 x (9)²
A = 3.14 x 81
A = 254.34 in²

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1 year ago

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Which is the graph of f(x) = -3√x? pls answer quickly

k0ka [10]

Answer: the graph farthest to the right is almost correct. If you substitute values for x in the function f(x)= -3√x , the output does not match the curve on the graphs shown.

If you have a choice that includes only a curve to the right of the y- axis, that would be better.

Step-by-step explanation: Square roots of Negative x-values will result in imaginary numbers. Otherwise the graph with the curve passing through coordinates (1,-3) (4,-6) and (9,-9) is a good choice.

(And ask your teacher about the square root of negative numbers on this graph.)

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2 years ago