Answer:
(i) 15 m, 6 m/s
(ii) 90 m
Step-by-step explanation:
(i) For some acceleration (a) from rest, the distance covered (d) in time t is ...
d = (1/2)at^2
The distance covered by Ben in the 5 seconds he is accelerating is ...
d = (1/2)(1.2 m/s²)(5 s)² = 15 m
Of course, Ben's speed at that point is ...
s = (1.2 m/s²)(5 s) = 6 m/s
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(ii) When Ben has been walking 5 s, Alan has been walking 10 s, so Alan has covered (10 s)(4 m/s) = 40 m. Their distance difference of 40 -15 = 25 m is being made up at the rate of their speed differences: (6 m/s) -(4 m/s) = 2 m/s.
It will take (25 m)/(2 m/s) = 12.5 s additional time for Ben to catch Alan. In the 22.5 s that Alan has been walking before they meet, he will have walked ...
(22.5 s)(4 m/s) = 90 m . . . the distance OP
Answer:
The solution to the system of equations is (1.6,-2)
Step-by-step explanation:
You have to plug the x which is -2 into the equation.
You would get y=2/3(-2)+3
Then you would calculate that to get y=1.6
Lastly you combine the y answer to the x answer to get the coordinates (1.6,-2)
Answer:
2*2=4, 9*2=18, so 2/9 = 4/18, 4 students are Minton walkers.
Step-by-step explanation:
4:3
x:39
We need to find what 3 was multiplied by to get 39:
39/3 = 13.
Now multiply 4 by this number
4*13 = 52
Hope this helped!