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MakcuM [25]
2 years ago
11

Rachel wants to collect data about the snack habits of her friends.

Mathematics
1 answer:
Pavel [41]2 years ago
7 0
<span>How many times a week do my friends eat snacks?

</span><span>How many of my friends like the same snack?

I'm not sure about this one, but I think it is:
</span><span>What time of the day are my friends most likely to eat a snack?</span>
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Can someone explain this to me not only answers make sure to make it clean then i will mark brainliest please i really need an e
Igoryamba

Answer:

Since the sum of the angles equal to 720, you have to add all the angles to add to 720 and then solve for x, in which would look like this (x+2)+(x-4)+(x+6)+(x-3)+(x+7)+(x-8)=720, which is simplified to (6x)=720, in which will make x=120. Next, since its angle E, you plug in tha x value, (120+6), in which the ANSWER IS 126 DEGREES

Step-by-step explanation:

Hope this help ^w^

4 0
2 years ago
Number of passengers who arrive at the platform in an amtrack train station for the 2 pm train on a saturday is a random variabl
alexgriva [62]
Assuming a normal distribution  we find the standardized z scores for  a:-

z1 = (80 - 180)  / 25  =  = -100/25  = -4
z2 =  (280-180) / 25  =  4
Required P( -4 < z < 4)  from the tables is  >99.9%

b
z1 = 130-180 / 25 =  -2
z2 =  230-180 / 25  = 2

from tables probability is 2* 0.4773  =  95.46 %
8 0
3 years ago
Which of the following is listed from least to greatest?
Blizzard [7]

Answer:

B. .002, .03, .6, .9

Step-by-step explanation:

.002 is .002

.03 is .030

.6 is .60

And, .9 is .90

So in conclusion, least to greatest would be .002 , .030 , .60 , then last but not least .90. The option that best matches this is B!

3 0
3 years ago
Read 2 more answers
Question 1 (Multiple Choice Worth 1 points)
Oksi-84 [34.3K]

Sorry I don't know but i bet more can exolain.

4 0
2 years ago
PLEase Hurry!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
mylen [45]

Answer: 56

Step-by-step explanation: Divide 42 by 3 and then multiply by 4

6 0
2 years ago
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