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Darina [25.2K]
3 years ago
13

-3(1 + p) = 8p - 36 SOLVe for p

Mathematics
1 answer:
gizmo_the_mogwai [7]3 years ago
5 0

Answer:

Step-by-step explanation:

-3(1+p)=8p-36

-3-3p=8p-36

+36 +3p | +3p +36

Simplifies to

33=11p

divide both side by 11

3=p thus p=3

You might be interested in
The total cost of painting of four walls of a square hall at Rs. 40 per sq. m. is Rs. 12000. If the hall contains 600 m³ of air,
astra-53 [7]

Answer:

The height of the hall is 9.375 meters

Step-by-step explanation:

The rate at which the walls of the square hall are painted, R = Rs. 40 per sq. m.

The total cost of painting the square hall, C = Rs. 12,000

The volume of air contained in the hall, V = 600 m³

The surface area of the four walls of the hall, A = C/A

∴ A = Rs. 12,000/(Rs. 40/m²) = 300 m²

Let 's' represent the length of sides of the square hall, and let 'h' represent the height of the square wall, we have;

The volume of the hall, V = s² × h

The surface area of the wall, A = 4 × s × h

Therefore, we get;

A = 300 = 4 × s × h

V = 600 = s² × h

V/A = 600/300 = 2 = s² × h/(4 × s × h) = s/4

s/4 = 2

s = 4 × 2 = 8

The side length of the square hall, s = 8 m.

From the area, A = 4 × s × h, we get;

A = 300 = 4 × 8 × h

h = 300/(4 × 8) = 9.375

The height of the hall, h = 9.375 m.

8 0
3 years ago
For numbers 1a-1d, tell wheaten the fractions are equivalent by selecting the correct symbol
Deffense [45]
What fractions? I see nothing...Do you have the choices?
5 0
4 years ago
What is the answer to 3-2
Natasha2012 [34]
The answer is 1.
3-2=1
5 0
3 years ago
Read 2 more answers
Fifteen years later, a man will be two times as old as he was 15 years ago. How old is he now?
Inga [223]

Answer:

Let the present age of the man be x years.

Age of the man 15 years ago =(x−15) years and

Age of the man 15 years later =(x+15) years

According to the given condition, we have

(x+15)=2(x−15)

⇒x+15=2x−30

⇒x−2x=−30−15

⇒−x=−45 or x=45 years

Hence, the present age of the man is 45 years.

Step-by-step explanation:

Hope it helps you..

Your welcome in advance..

(◍•ᴗ•◍)

6 0
3 years ago
Read 2 more answers
HELP PLEASE!!! I need help with this question!
AlexFokin [52]

Answer:

\large\boxed{PS=10\sqrt5}

Step-by-step explanation:

ΔPQS, ΔRQP and ΔRPS are similar (AA). Therefore the sides are in proportion:

\dfrac{QR}{RP}=\dfrac{RP}{RS}

We have:

QR=5,\ RS=20

Substitute:

\dfrac{5}{RP}=\dfrc{RP}{20}                <em>cross multiply</em>

RP^2=(5)(20)\\\\RP^2=100\to RP=\sqrt{100}\\\\RP=10

Use the Pythagorean theorem:

PS^2=PR^2+RS^2

Substitute:

PS^2=10^2+20^2\\\\PS^2=100+400\\\\PS^2=500\to PS=\sqrt{500}\\\\PS=\sqrt{100\cdot5}\\\\PS=\sqrt{100}\cdot\sqrt5\\\\PS=10\sqrt5

6 0
3 years ago
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