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3 years ago

-3(1 + p) = 8p - 36 SOLVe for p

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

5 0

Answer:

Step-by-step explanation:

-3(1+p)=8p-36

-3-3p=8p-36

+36 +3p | +3p +36

Simplifies to

33=11p

divide both side by 11

3=p thus p=3

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Need help with my homework

Volgvan

Answer:

$\displaystyle y=\frac{16-9x^3}{2x^3 - 3}$

$\displaystyle y=-\frac{56}{13}$

Step-by-step explanation:

<u>Equation Solving</u>

We are given the equation:

$\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}$

To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.

We have to make it in steps like follows.

Cube both sides:

$\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3$

Simplify the radical with the cube:

$\displaystyle x^3=\frac{3y+16}{2y+9}$

Multiply by 2y+9

$\displaystyle x^3(2y+9)=\frac{3y+16}{2y+9}(2y+9)$

Simplify:

$\displaystyle x^3(2y+9)=3y+16$

Operate the parentheses:

$\displaystyle x^3(2y)+x^3(9)=3y+16$

$\displaystyle 2x^3y+9x^3=3y+16$

Subtract 3y and $9x^3$ :

$\displaystyle 2x^3y - 3y=16-9x^3$

Factor y out of the left side:

$\displaystyle y(2x^3 - 3)=16-9x^3$

Divide by $2x^3 - 3$ :

$\mathbf{\displaystyle y=\frac{16-9x^3}{2x^3 - 3}}$

ii) To find y when x=2, substitute:

$\displaystyle y=\frac{16-9\cdot 2^3}{2\cdot 2^3 - 3}$

$\displaystyle y=\frac{16-9\cdot 8}{2\cdot 8 - 3}$

$\displaystyle y=\frac{16-72}{16- 3}$

$\displaystyle y=\frac{-56}{13}$

$\mathbf{\displaystyle y=-\frac{56}{13}}$

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2 years ago

Can you answer this step by step? 31,398 ÷ 65 =

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Answer:

483 with a remainder of 3

Step-by-step explanation:

4 8 3

---------------------------------

6 5 | 3 1 3 9 8

2 6 0

------------------

5 3 9

5 2 0

---------------------

1 9 8

1 9 5

------------------------------

Hope I explain myself :/

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tatyana61 [14]

Answer:

the answer should be 9/14

Step-by-step explanation:

you add them all up then subtract the red for your denominator

then just put the number of white on top for your numerator

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Step-by-step explanation:

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