Question

Pls help me!!

Answer 1

Answer:

Q1

The graph of y = f(x), has vertex at (1, -2)

The vertex of a function f(x - 3) is going to be:

• (1 - 3, -2) = (-2, -2)

Q2

• The graph of y = f(x) has the line x = 5 as an axis of symmetry. The graph also passes through the point (8,-7). Find another point that must lie on the graph of y = f(x).

The axis of symmetry is at the same distance from the symmetric points.

x = 5 is a vertical line. The point (8, -7) is 3 units to the right. So the mirror point will be 3 units to the left and have same y-coordinate: x = 5 - 3 = 2

The point is (2, -7)

Q3

The graph in blue is the translation of the red to the left by 2 units.

So the equation is:

• y = f(x + 2)

Q4

y = h(x) is graphed

• h(7) = 5
• h(h(7)) = h(5) = -1

Q5

The graph of the function y = u(x) given

This is a odd function.

The coordinates of u(x) and u(-x) add to zero because u(-x) = -u(x)

Therefore:

• u(-2.72) + u(-0.81) + u(0.81) + u(2.72) =
• [u(-2.72) + u(2.72)] + [u(-0.81) + u(0.81)] =
• 0 + 0 = 0