Ask question

Ask question

All categories

3 years ago

14

Jane exchanged £100 for 216 Swiss francs. After buying a meal and a present to take home,she had 70 francs left.How much is this

in £?

1 answer:

mrs_skeptik [129]3 years ago

8 0

Answer:

£32.4

Step-by-step explanation:

£100 = 216 Swiss francs

x = 70 francs

70 x 100=7000/216=32.4

You might be interested in

Kendra is making a large salad for a party. She buys lettuce for $2.25 per pound and tomatoes for $2.65 per pound. She spends at

PSYCHO15rus [73]

2.25x + 2.65y > = 8 (thats greater then or equal)

3 0

4 years ago

Shelly completed 10 problems of her homework in study hall. Thi sis 2/7 of the total assignment. How many problems does she have

Lerok [7]

Okay, so I just take 10 divided 2/7 to get 35 problems which is the total problems that Shelly has. Next, I already know that she did 10 problems, and she will just have 25 problems left.

6 0

3 years ago

Write both inequalities graphed above?

sdas [7]

Answer:

no identity will escape! I know where you live

4 0

3 years ago

5 times p squared times q+ 10q

Basile [38]

Answer:

5*p^2*q+10q = 5p^2*q + 10q

Step-by-step explanation:

5 * p squared * q + 10q = 5p^2*q+10q

5 0

3 years ago

If f(x) = 3x2 − 8x, 0 ≤ x ≤ 3, evaluate the Riemann sum with n = 6, taking the sample points to be right endpoints.

denis23 [38]

Split up the interval [0, 3] into 6 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], [3/2, 2], [2, 5/2], [5/2, 3]

The right endpoints are given by the arithmetic sequence,

$r_i=0+\dfrac i2=\dfrac i2$

with $1\le i\le6$ .

We approximate the integral of $f(x)$ on the interval [0, 3] by the Riemann sum,

$\displaystyle\int_0^3f(x)\,\mathrm dx=\sum_{i=1}^6f(r_i)\Delta x_i$

$\displaystyle=\frac{3-0}6\sum_{i=1}^6\left(3{r_i}^2-8r_i\right)$

$\displaystyle=\frac12\sum_{i=1}^6\left(\frac{3i^2}4-4i\right)$

$\displaystyle=\frac38\sum_{i=1}^6i^2-2\sum_{i=1}^6i$

Recall the formulas,

$\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2$

$\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6$

Then the value of the integral is approximately

$\displaystyle=\frac38\cdot\frac{6\cdot7\cdot13}6-2\cdot\frac{6\cdot7}2=\boxed{-\frac{63}8}=-7.875$

Compare to the exact value of the integral, -9.

7 0

3 years ago