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Zielflug [23.3K]
3 years ago
7

If f(x) = 3x2 − 8x, 0 ≤ x ≤ 3, evaluate the Riemann sum with n = 6, taking the sample points to be right endpoints.

Mathematics
1 answer:
denis23 [38]3 years ago
7 0

Split up the interval [0, 3] into 6 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], [3/2, 2], [2, 5/2], [5/2, 3]

The right endpoints are given by the arithmetic sequence,

r_i=0+\dfrac i2=\dfrac i2

with 1\le i\le6.

We approximate the integral of f(x) on the interval [0, 3] by the Riemann sum,

\displaystyle\int_0^3f(x)\,\mathrm dx=\sum_{i=1}^6f(r_i)\Delta x_i

\displaystyle=\frac{3-0}6\sum_{i=1}^6\left(3{r_i}^2-8r_i\right)

\displaystyle=\frac12\sum_{i=1}^6\left(\frac{3i^2}4-4i\right)

\displaystyle=\frac38\sum_{i=1}^6i^2-2\sum_{i=1}^6i

Recall the formulas,

\displaystyle\sum_{i=1}^ni=\frac{n(n+1)}2

\displaystyle\sum_{i=1}^ni^2=\frac{n(n+1)(2n+1)}6

Then the value of the integral is approximately

\displaystyle=\frac38\cdot\frac{6\cdot7\cdot13}6-2\cdot\frac{6\cdot7}2=\boxed{-\frac{63}8}=-7.875

Compare to the exact value of the integral, -9.

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Solve the value for v.
NemiM [27]

Answer:

Hey mate !!

Your answer is so simple :)

<h2>V= 9°</h2>

Go through the explanation to understand.

Step-by-step explanation:

In the given question,

We see that 105° and it's adjacent angle (i.e. 8v+3° ) forms a supplementary angle. Which means the sum of 8v+3°+105° is 180°

<h3>Therefore,</h3>

According to the question

105 + 8v + 3 = 180

=  > 105 + 8v = 180 - 3

=  > 8v =  177 - 105

=  > 8v = 72

=  > v =  \frac{72}{8}

=  > v = 9

Answer the value of v is 9° .

Hope it helps you!!

#IndianMurga ツ

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3 years ago
I need help with all three letters. thank u
creativ13 [48]

Answer:

Step-by-step explanation:

A to C

y = b + mx

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Looking at the line, the line crosses the y-axis at the coordinates (0,0). This means that the y-intercept is 0.

The slope formula is m=(y2-y1)/(x2-x1). Using the points on the line (-1, -3) and (1,3) we find that the slope is, 3.

Looking back we can see that our variables now have value so we can plug them into our formula.

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