<u>Answer:</u>
<em>The purpose of including boot in a nontaxable exchange is to equalize the adjusted tax bases of the properties exchanged.
</em>
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<u>Explanation:</u>
A nontaxable exchange is a trade wherein you are not exhausted on any addition, and you cannot deduct any loss. On the off chance that you get property in a "nontaxable business", its premise usually is equivalent to the assumption of the property you moved. A nontaxable increase or misfortune is otherwise called an unrecognized addition or misfortune.
Answer:
A)
risk free rate = 8%
market rate = 15%
Xyrong's beta = 1.2
pays 40% of income in dividends
latest EPS = $10
ROE = 18%
k = 8% + (1.2 x 7%) = 16.4%
g = ROE x (1 - 40%) = 10.8%
div1 = [(40% x $10) x (1 + g)] = $4 x 1.108 = $4.432
stock price = $4.432 / (16.4% - 10.8%) = $79.14
B)
div0 = $4
div1 = $4.432
price0 = $103
price1 = $79.14 x (1 + g) = $79.14 x 1.108 = $87.69
holding period return = ($4.43 + $87.69 - $103) / $103] = -0.1056 or -10.56%
<span>The corporate social
responsibility is the task of every individual in the corporation to balance
between economy and the ecosystems. It is related to the triple bottom line because
it includes social, environmental and financial responsibility.</span>
The call in this scenario is known as Out of the money (OTM).
Out of the money is when an option has no intrinsic value but rather, has an extrinsic value.
- Here, the current stock price is below the strike price of 201,then, we say that the call is out of money.
- A call option is called Out of the money when the underlying price is trading below the strike price of the call.
Hence, the call in this scenario is known as Out of the money (OTM)
Read more about Out of the money (OTM):
<em>brainly.com/question/15684431</em>
Answer:
The probability of Ann winning the prize is 2.464
Explanation:
The probability of Ann winning the prize can be analysed as potray below
1.pr(of Ann being the first player selected).
Here Ann plays the 2nd,3rd and 4th player to win prize,the probability=0.8×0.8×0.8=0.512
2.Pr(of Ann being the second player selected)
If Ann is randomly selected as the second player,she will still need to play three matches to win with 1st,3rd and 4th
0.8×0.8×0.8=0.512
3.Pr(of Ann. Being the third player chooses randomly),Ann will get to play just two players i.e the winner of 1and 2 and the 4th.the probability=0.8×0.8=0.64
4.Pr(of Ann being the 4th player choosen randomly)
Ann gets to play only one match to win the prize in this scenario
So probability of a Ann win is 0.8
Total probability a Ann winning the prize=0.512+0.512+0.64+0.8=2.464
