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Kipish [7]
3 years ago
8

How do you solve (2y^2)^3 x 2y^3

Mathematics
2 answers:
andrew-mc [135]3 years ago
8 0

Answer:

8y^6,2xy^3

Step-by-step explanation:

balu736 [363]3 years ago
8 0
Hope it helps !!!!!!!!!!!

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4. Over the span of a month, a school tracks student choices at lunch. They 1 point
Darina [25.2K]

Answer:

b

Step-by-step explanation:

56 +32 =88

88 - 22 = 66 remove this who did both as to not double count

100-66=34 bought neither

5 0
3 years ago
Read 2 more answers
Questions and answers attached
Black_prince [1.1K]

Answer:

(3)(c) + 43 ≥ 100

Step-by-step explanation:

Given:

Total number of friends = 3 friends

Number of card already have = 43

Total number of card at least want to collect = 100

Find:

Inequality

Computation:

Assume;

Same number of card each friend collect = c

Total number of card at least want to collect ≤ (Total number of friends)(Same number of card each friend collect) + Number of card already have

Total number of card at least want to collect ≤ (3)(c) + 43

100 ≤ (3)(c) + 43

(3)(c) + 43 ≥ 100

3 0
3 years ago
g A researcher wants to construct a 95% confidence interval for the proportion of children aged 8-10 living in Atlanta who own a
Helga [31]

Answer:

The sample size needed is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error of the interval is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Estimate the sample size needed if no estimate of p is available so that the confidence interval will have a margin of error of 0.02.

We have to find n, for which M = 0.02.

There is no estimate of p available, so we use \pi = 0.5

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.02\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.02}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.02})^{2}

n = 2401

The sample size needed is 2401.

7 0
3 years ago
Read 2 more answers
The base parking charge at a mall on a Sunday is $2 per hour. If a vehicle is parked for 4 hours, only $6 is charged. What perce
chubhunter [2.5K]
2 dollars = 1 hour
8 dollars = 4 hours
she paid 6 dollars so the amount saved = 8-6 = 2 dollars
percentage saved = \frac{2}{8} × 100
percentage saved = 25%

7 0
3 years ago
Read 2 more answers
Solve. x2 + 14 = 9x A) x = 2, x = 7 B) x = 3, x = 5 C) x = −2, x = −7 D) x = −3, x = −5
chubhunter [2.5K]

Answer:

A) x = 2, x = 7

Step-by-step explanation:

x^2 + 14 = 9x

Subtract 9x from each side

x^2-9x + 14 = 9x-9x

x^2-9x + 14 = 0

What 2 numbers multiply to 14 and add to -9

-7*-2 = 14

-7+-2 = -9

(x-7)(x-2) = 0

Using the zero product property

x-7 = 0   x-2 =0

x=7   x=2

7 0
3 years ago
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