MCE = 360 - (150 + 70 + 50)
mCE = 360 - 270
mCE = 90
<CDE = 1/2(mBE + mCE)
<CDE = 1/2(150 + 90)
<CDE = 1/2(240)
<CDE = 120
answer
<CDE = 120°
I’m not sure but maybe true
Answer:
Step-by-step explanation:
Comparing it with quadratic equation 
, we get:
a = 1 . b = 4 and c = 5
So,
Discriminant = 
D = (4)²-4(1)(5)
D = 16 - 20
D = -4
Hence,
Discriminant = -4
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3 /><h3>~AH1807</h3>
Answer:
Step-by-step explanation:
So the distance that he ran is 30 yards since he ran from the 10 to 40 yard line. making it 30 yards. It is then said he ran this in 10 seconds
Now all you have to do is divide 30yards by 10seconds to see how many yards he ran in a sec. Dividing it you get 3 yards per second
