(6y - 11)(6y + 11) = ay
² - b |use (a - b)(a + b) = a² - b²
(6y)² - 11² =ay² - b
36y² - 121 = ay² - b |add b to both sides
ay² = 36y² - 121 + b |divide both sides by y² ≠ 0
a = (36y² - 121 + b)/y²
Answer:
0.00114
Step-by-step explanation:
Divide length value by 5280
So the equation you're going to be using is mass = density x volume
So the volume of your block is 35cm^3, and your density is .85g/ml
so your equation would be
mass=.85g/ml x 35cm^3
your final answer is 29.75g/cm^3
Hope this helps :)
Given,
The expression is,
If x- 3 is the factor of the given polynomial function, then on substituting the value of x = 3 in the polynomial function, it become zero.
Thus subsituting the value of x in the polynomial,
Here, the obtained value of polynomial is 0.
Hence, x-3 is a factor of the given polynomial.
Thus, option A(true) is correct.
