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3 years ago

Solve for the variable x m = -12g + x

Mathematics

1 answer:

mario62 [17]3 years ago

3 0

Answer:

x=m+12g

Step-by-step explanation:

m=-12g+x

making x subject of formula, we have,

x=m+12g

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For the graphed function f(x) = −(5)x − 3 + 2, calculate the average rate of change from x = 3 to x = 4.

azamat

Answer:

-4 is the average rate of change from 3 to 4

Step-by-step explanation:

Average rate of change is defined as the fraction of change in f(x) value to change in x value.

Here we have x values as 3 and 4.

To find the average rate of change from x=3 to x=4

Average rate of change = change in f(x)/change in x

f(4) = -5^{4-3} +2 = -3\\f(3) = 1\\f(4)-f(3) = -3-1 =-4

Change in x = 4-3 =1

6 0

3 years ago

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Lakshmi planted 20 begonias, but her neighbor’s dog ate 7 of them. What percent of the begonias did the dog eat

Leona [35]

Answer:

100 / 20 = 5

5 * 7 = 35

So the dog ate 35% of it

Step-by-step explanation:

yea so your welcome. im 7 btw

7 0

3 years ago

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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,

omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

Pyramid A

$s = 4$ -- base sides

$V = 36$ -- Volume

Pyramid B

$s = 6$ --- base sides

Required

Determine the volume of pyramid B [Missing from the question]

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

$V = \frac{1}{3} * B * h$

Where B represents the area of the base equilateral triangle, and it is calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

$B = \frac{1}{2} * s^2 * sin(60)$

$B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}$

$B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}$

$B = 4\sqrt 3$

The height is calculated from:

$V = \frac{1}{3} * B * h$

This gives:

$36 = \frac{1}{3} * 4\sqrt 3 * h$

Make h the subject

$h = \frac{3 * 36}{4\sqrt 3}$

$h = \frac{3 * 9}{\sqrt 3}$

$h = \frac{27}{\sqrt 3}$

To calculate the volume of pyramid B, we make use of:

$V = \frac{1}{3} * B * h$

Since the heights of both pyramids are the same, we can make use of:

$h = \frac{27}{\sqrt 3}$

The base area B, is then calculated as:

$B = \frac{1}{2} * s^2 * sin(60)$

Where

$s = 6$

So:

$B = \frac{1}{2} * 6^2 * sin(60)$

$B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}$

$B = 9\sqrt 3$

So:

$V = \frac{1}{3} * B * h$

Where

$B = 9\sqrt 3$ and $h = \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}$

$V = \frac{1}{3} * 9 * 27$

$V = 81$

6 0

3 years ago

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SOMEONE PELASE HELP ME ASAP! I REALLY NEED HELP ASAP

Stells [14]

Answer: below in picture

explanation: also in picture

6 0

3 years ago

6 sin _ _ 3 csc _ = 0

mamaluj [8]

6 sin θ - 3 csc θ = 0
6 sin θ = 3 csc θ = 3/sin θ
6 sin^2 θ = 3
sin^2 θ = 3/6 = 1/2
sin θ = sqrt(1/2)
θ = arcsin(sqrt(1/2)) = 45 degrees.
θ = 45°

6 0

3 years ago