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Maru [420]
3 years ago
6

Help me answer this but hurry please!

Mathematics
1 answer:
Andrew [12]3 years ago
4 0

Answer:

165°

Step-by-step explanation:

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PLEASE HELP. WILL GIVE BRAINLIEST
KengaRu [80]

Answer:

x-intercepts = 1,2, and 4, y-intercept = -8

Step-by-step explanation:

x^3 - 7x^2 - 14x - 8 in factored form is equal to (x-1)(x-2)(x-4).

Solving for x-intercepts:

  • We are actually able to solve for all x-intercepts without the given factor. But since we are given one of the factors, our job becomes much easier.
  • Using synthetic division, or long division, we factor out the x-intercept 4. Which leaves us with the polynomial x^2 - 3x + 2.
  • From here we can separate the polynomial into two binomials.
  • x^2 - 3x + 2 = (x-1)(x-2). Giving us all 3 x-intercepts.
  • Using Descartes' rules we can identify before even starting the problem how many real x-intercepts there are (Not needed for this problem).

Solving for y-intercept:

  • The y-intercept is always the coefficient that does not have any assigned x-variables.
  • The coefficient is -8, thus the y-intercept.
  • If unsure of the y-intercept, you can always plug in x = 0. Solving for the y-intercept will give you the value of f(0).
  • If there is no coefficient, the y-intercept is equal to zero.
4 0
3 years ago
An oak tree is planted when it is 650 centimeters tall. What is this height in meters?
Mashutka [201]

Answer:

It is 6.5 meters

The centimeter practical unit of length for many everyday measurements. A centimeter is equal to 0.01(or 1E-2) meter.

7 0
3 years ago
Eights rooks are placed randomly on a chess board. What is the probability that none of the rooks can capture any of the other r
erastova [34]

Answer:

The probability is \frac{56!}{64!}

Step-by-step explanation:

We can divide the amount of favourable cases by the total amount of cases.

The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8, 64 \choose 8 .

For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function  f : A \rightarrow A , with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.

Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.

We can conclude that the probability for 8 rooks not being able to capture themselves is

\frac{8!}{64 \choose 8} = \frac{8!}{\frac{64!}{8!56!}} = \frac{56!}{64!}

7 0
2 years ago
In the figure above, sin 52=17/c. Based on the figure, which of the following equations is also true
Art [367]

Answer:

c. Cos 52 = 17/c

Step-by-step explanation:

sin(x) = cos(90-x)

7 0
2 years ago
Simplify: <br> (sq root of) a^2 if a&gt;0<br><br> (sq root of) 36x^2 if x≤0
tresset_1 [31]

Answer:


Step-by-step explanation:

1.  (sq root of) a^2 if a>0 => √(a^2) = ±a

2.  (sq root of) 36x^2 if a>0 => ±6x

7 0
3 years ago
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