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pogonyaev
3 years ago
15

5/6 +3/7 give answer as a mixed number

Mathematics
2 answers:
Lyrx [107]3 years ago
5 0

Answer:

1\frac{11}{42}

Step-by-step explanation:

  1. \frac{5}{6} = \frac{35}{42}  
  2. \frac{3}{7} = \frac{18}{42}  
  3. \frac{35}{42} + \frac{18}{42} = \frac{53}{42}  
  4. \frac{53}{42} = 1\frac{11}{42}  

I hope this helps!

Bogdan [553]3 years ago
5 0

Answer:

56/42, or 1 14/42

Step-by-step explanation:

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For her presentation on the Wonders of the World, Mary baked a square pyramid-shaped cake as pictured below. The slant height of
mihalych1998 [28]

Answer:

V=196in^3

Step-by-step explanation:

The volume of a pyramid is:

V=\frac{A_{b}h}{3}

where A_{b} is the area of the base and h is the height (the perpendicular measurement between base and highest point, not the slant height)

Since the base is a square, the area is given by:

A_{b}=l^2

where l is the length of the side: l=8in, thus:

A_{b}=(8in)^2\\A_{b}=64in^2

Now we need to find the height, for this we use the right triangle that forms with half of a square side (8in/2 = 4in), the slant height (10in), and the height.

In this right triangle, the slant height is the hypotenuse, the leg 1 is the unknown height, and leg 2 is half of the square side.

Using pythagoras:

hypotenuse^2=leg1^2+leg2^2

substituting our values, and indicating that leg 1 is height h:

(10in)^2=h^2+(4in)^2

100in^2=h^2+16in^2

and solving for the height:

h^2=100in^2-16in^2\\h^2=84in^2\\h=\sqrt{84in^2}\\ h=9.165in

and finally we calculate the volume using this height and the area of the base:

V=\frac{A_{b}h}{3}

V=\frac{(64in^2)(9.165in)}{3} \\V=195.5in^3

rounding to the nearest cubic inch: V=196in^3

4 0
4 years ago
A tin man has a head that is a cylinder with a cone on top. the height of the cylinder is 12 inches and the height of the cone i
lisov135 [29]
I believe your answer is b.
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3 years ago
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3 years ago
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Solve for the following equation step by step and justify your steps when using an exponential property.
mel-nik [20]

x = \frac{5}{7}

using the ' laws of exponents '

• a^{m} × a^{n} = a^{( m + n )}

•  a^{m} ÷ a^{n} = a^{(m - n)}

• (a^{m})^n = a^{mn}

7^{2} × 7^{3} = 7^{5} ÷ 7^{3x} = 7^{5 - 3x}

7^{4x} = 7^{5 - 3x}

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4x = 5 - 3x

7x = 5 ⇒ x =\frac{5}{7}




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3 years ago
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