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9966 [12]
3 years ago
9

What value of p will make the expression below a perfect square? x^2 - x + P

Mathematics
2 answers:
pentagon [3]3 years ago
8 0

Answer:

x^2 - x + 1/4

Step-by-step explanation:

To complete the square

x^2 - x + P

Take the coefficient of x

-1

Divide by 2

-1/2

Then square it

(-1/2)^2

1/4

Add this to complete the square

x^2 - x + 1/4

shutvik [7]3 years ago
6 0

Answer:

p = \frac{1}{4}

Step-by-step explanation:

To make a perfect square

add ( half the coefficient of the x- term )² to x² - x, that is

x² + 2(- \frac{1}{2} )x + \frac{1}{4} with p = \frac{1}{4} , thus

x² - x = (x - \frac{1}{2} )² + \frac{1}4}

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Answer: 14

Step-by-step explanation:

131 (total cost of tickets)- 5 (service charge) = 126 cost of tickets

126/9= 14 dollars a ticket

(c= cost)

131-5=c

126/9=14

Hope this helped

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2 years ago
QUESTION 10 of 10: Your plan for your T-shirt business calls for you to be able to produce 60,000 screen printed shirts in a mon
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Step-by-step explanation:

i got the right answer

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2 years ago
BRAINLY PLS HELP ME OUT ON THE 5,2 what the m value I beg you ASP
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Answer:

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=> 25 = 4 + m²

=> 25–4 = m²

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8 0
3 years ago
How much money does the average professional hockey fan spend on food at a single hockey​ game? That question was posed to 10 ra
Vinil7 [7]

Answer:

Now we have everything in order to replace into formula (1):

18-2.262\frac{2.75}{\sqrt{10}}=16.03    

18+2.262\frac{2.75}{\sqrt{10}}=19.97    

Step-by-step explanation:

Information given

\bar X=18 represent the sample mean

\mu population mean (variable of interest)

s=2.75 represent the sample standard deviation

n=10 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=10-1=9

The Confidence is 0.90 or 90%, the significance is \alpha=0.1 and \alpha/2 =0.05, and the critical vaue would be t_{\alpha/2}=2.262

Now we have everything in order to replace into formula (1):

18-2.262\frac{2.75}{\sqrt{10}}=16.03    

18+2.262\frac{2.75}{\sqrt{10}}=19.97    

5 0
2 years ago
Consider the graph of the quadratic function. Which interval on the x-axis has a negative rate of change?
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The average rate of change is defined as:

AVR = \frac{f(x2)-f(x1)}{x2-x1}

For AVR to be negative, it must comply with:

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f (x2)

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3 0
3 years ago
Read 2 more answers
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