Answer:the 57th term is 78
Step-by-step explanation:
The sequence is an arithmetic sequence. The formula for determining the nth term of an arithmetic sequence is expressed as
Tn = a + (n - 1)d
Where
a represents the first term of the sequence.
d represents the common difference.
n represents the number of terms in the sequence.
From the information given,
a = - 6
d =3/2
n = 57
We want to determine the value if the 57th term, T57. Therefore,
T57 = - 6 + (57 - 1) ×3/2
T57 = - 6 + 56 × 3/2 = - 6 + 84
T57 = 78
Answer:
a). ∠D = 56°
b). AD = √13
Step-by-step explanation:
(a) From the figure attached, ABCD is a trapezoid with parallel sides AB and CD. We have to find the measure of ∠D from the given figure.
From triangle ADE,
D =
D = 56.31
D ≈ 56°
Therefore, measure of ∠D is 56°.
(b). Now by applying Pythagoras theorem in ΔADE,
AD² = AE² + DE²
= 3² + 2²
AD² = 9 + 4
AD = √13
Length of AD is √13 in.
Answer:
1. Yes the parentheses are necessary. To find a fourth of her regular hours you must find the total amount she works during her regular hours.
2. 6
Step-by-step explanation:
(For the second question)
4+8= 12
12 × ½ = 12 ÷ 2
12÷2 = 6
Answer:
John is running faster.
Step-by-step explanation:
Given that:
Average Speed of Anne = 6 miles per hour
Speed of John can be represented in the table below:
To find:
Who is running faster of the both i.e. Anne and John?
Solution:
Here, to find the faster runner we can compare the average speed of both the runners.
We are given that, average speed of Anne = 6 miles per hour
We will have to calculate the average speed of John to find the faster runner.
<em>Average speed</em> can be calculated by dividing the total distance traveled with the total time taken.
Total distance traveled by John = 11.5 - 1 = 10.5 miles
Total time taken by John = 1.5 hours
Average speed of John =
Clearly Average speed of John is greater than that of Anne's.
Therefore, <em>John runs faster</em>.