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3 years ago

1 L of a 78% acid solution was mixed with 6 L of a 64% acid solution. Find the concentration of the new mixture.

Mathematics

1 answer:

JulijaS [17]3 years ago

8 0

The first solution contributes 0.78*1 = 0.78 L of acid.

The second contributes 0.64*6 = 3.84 L of acid.

There will be 7 L total of the new solution, and 3.84 + 0.78 = 4.62 total L of acid in it. So the new solution has a concentration of 4.62/7 = 0.66, or about 66%.

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Please answer i need help!!!!! WILL GIVE BRAINLIEST!!!!!

sp2606 [1]

1. D. 4 x 4 x 4 x 4 x 4

2. B. 6³ (6 x 6 x 6 = 216)

3. D. (8², 100^1, 11², 5³)

4. D. Sum (There's No addition anywhere in that equation)

5. C. h (Because there's no number before the h²)

6. C. 24

7. C. Raise 9 to the 2nd power (Follow PEMDAS, after doing the parentheses, you need to do the exponents, and C. you need to the exponents)

8. A. 4xy

9. C. 18 (I followed PEMDAS, and received the answer 18)

10. B. 49

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I hope this helps, and Happy Holidays! :)

4 0

2 years ago

If f(x)=2x+5, then f(4) represents what

RSB [31]

f(x)=2x+5
then
f(4)=2(4) +5 = 8 + 5 = 13

hope it helps

6 0

3 years ago

Use spherical coordinates. Find the volume of the solid that lies within the sphere x^2 + y^2 + z^2 = 81, above the xy-plane, an

Natasha_Volkova [10]

Answer:

The volume of the solid is 243 $\sqrt{2} \ \pi$

Step-by-step explanation:

From the information given:

BY applying sphere coordinates:

0 ≤ x² + y² + z² ≤ 81

0 ≤ ρ² ≤ 81

0 ≤ ρ ≤ 9

The intersection that takes place in the sphere and the cone is:

$x^2 +y^2 ( \sqrt{x^2 +y^2 })^2 = 81$

$2(x^2 + y^2) =81$

$x^2 +y^2 = \dfrac{81}{2}$

Thus; the region bounded is: 0 ≤ θ ≤ 2π

This implies that:

$z = \sqrt{x^2+y^2}$

ρcosФ = ρsinФ

tanФ = 1

Ф = π/4

Similarly; in the X-Y plane;

z = 0

ρcosФ = 0

cosФ = 0

Ф = π/2

So here; $\dfrac{\pi}{4} \leq \phi \le \dfrac{\pi}{2}$

Thus, volume: $V = \iiint_E \ d V = \int \limits^{\pi/2}_{\pi/4} \int \limits ^{2\pi}_{0} \int \limits^9_0 \rho ^2 \ sin \phi \ d\rho \ d \theta \ d \phi$

$V = \int \limits^{\pi/2}_{\pi/4} \ sin \phi \ d \phi \int \limits ^{2\pi}_{0} d \theta \int \limits^9_0 \rho ^2 d\rho$

$V = \bigg [-cos \phi \bigg]^{\pi/2}_{\pi/4} \bigg [\theta \bigg]^{2 \pi}_{0} \bigg [\dfrac{\rho^3}{3} \bigg ]^{9}_{0}$

$V = [ -0+ \dfrac{1}{\sqrt{2}}][2 \pi -0] [\dfrac{9^3}{3}- 0 ]$

V = 243 $\sqrt{2} \ \pi$

4 0

2 years ago

Y=4x-18 Find ordered pairs of intercepts of each line

Masja [62]

The ordered pairs for the intercepts are as follows:

x intercept = 9/2

y intercept = -18

In order to find either of these you must put 0's in for the other variable. So, to find the x intercept, we start by putting 0 in for y.

y = 4x - 18

0 = 4x - 18

-4x = -18

x = 9/2

To find the y intercept, we put a 0 in for x.

y = 4x - 18

y = 4(0) - 18

y = 0 - 18

y = -18

5 0

2 years ago

Plot the image of D under a dilation about the origin (0,0) with a scale factor of 2

ElenaW [278]

(-6,-4)

If you dilate a point, (c,d) about (a,b) by a scale factor by k. You'll going to subtract each coordinates where the point will be dilated about (a,b) from the point (c,d) and then multiply them by k. This would be the formula if you want: (k(c -a), k(b -d))

Let's say F is the dilation of D about the origin or (0,0) then the x coordinate of F would be

$x = 2( - 3 - 0) \\ x = 2( - 3) \\ x = - 6$

This would be the y coordinate of F:

$y = 2( - 2 - 0) \\ y = 2( - 2) \\ y = - 4$

Thus the coordinates of F is (-6,-4)

4 0

2 years ago