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Luden [163]
3 years ago
6

6-8 weeks i hope this help:)

Mathematics
1 answer:
Nastasia [14]3 years ago
6 0

Answer:

I have no idea but okay

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mixas84 [53]
The answer to the first question is 9
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3 years ago
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Which description best compares the graph of y-3=-2(×+4)andy=-2×_5
rjkz [21]
Rewrite the first function so that the two functions are in standard form:

y - 3 = -2x - 8  => y = 3 - 2x - 8  =>  y = -2x - 5

and

y= -2x - 5

We can now see immediately that these two functions have the same slope (-2) and same y-intercept (providing that you meant "y = -2x - 5).

The graphs of these 2 functions are identical.

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3 years ago
Write each percent as a fraction as a decimal.<br> 1. 222% 2. 0.9%
andrew-mc [135]

Answer:

222/100

9/1000

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3 years ago
How can you use graphing to determine whether (5,2) is a solution to the system of inequalities
Kisachek [45]

Answer:

You can use graphing to determing whether (5, 2) is a solution to the system of inequalities by creating a line going from the origin (0,0) and bring the line to (5, 2). Using this, you can find the x & y intercept, slope, etc.

Step-by-step explanation:

8 0
3 years ago
The sick days of employees every two years in a company are normally distributed with a population standard deviation of 7 days
Alecsey [184]

Answer:

The 95% confidence interval for the population mean is between 17.93 days and 24.07 days.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

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M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.96\frac{7}{\sqrt{20}} = 3.07

The lower end of the interval is the sample mean subtracted by M. So it is 21 - 3.07 = 17.93 days

The upper end of the interval is the sample mean added to M. So it is 21 + 3.07 = 24.07 days

The 95% confidence interval for the population mean is between 17.93 days and 24.07 days.

7 0
3 years ago
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