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ryzh [129]
3 years ago
13

Solve for x 3(X-5)-4X = 6(X-10) -(X+ 5)

Mathematics
1 answer:
Contact [7]3 years ago
6 0
X=8.33
u have to isolate the x on a side ans the numbers on the other side of the equation
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If a triangle with vertices A(-1, 4), B(-1, -2), C(2, -2) is dilated with a scale factor of 2 and a center of dilation at the or
givi [52]

Answer:

A' (-2,8) B' (-2,-4) C' (4,-4)

Step-by-step explanation:

Dilations Rule :

(x,y) → (kx,ky)

Scale factor = K

When your scale factor is more than one our triangle gets bigger. When your scale factor is less than one our triangle gets smaller.

( you plug in 2 in every point and those are your answers).

Remember negative times negative is positive and positive times negative is negative.

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Add. Enter a number only as your answer in the space provided<br><br><br> Please I really need help
Andreas93 [3]

Answer:0

Step-by-step explanation:

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3 years ago
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You use 8 cups of flour to make 24 muffins at that rate how much flour will it take to make 30 muffins
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Is 14/35 and 21/42 proportional
PIT_PIT [208]
1.Simplified each one 
2/5 (both divided by 7) ,  1/2 (divided by 21)
2.Make them into integer
(2/5 )*(2/2)=4/10    ,    (1/2)*(5/5)=5/10
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8 0
3 years ago
3x^2+kx=-3 What is the value of K will result in exactly one solution to the equation?
Scorpion4ik [409]

Answer:

For k = 6 or k = -6, the equation will have exactly one solution.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

If \bigtriangleup = 0, the equation has only one solution.

In this problem, we have that:

3x^{2} + kx + 3 = 0

So

a = 3, b = k, c = 3

\bigtriangleup = b^{2} - 4ac

\bigtriangleup = k^{2} - 4*3*3

\bigtriangleup = k^{2} - 36

We will only have one solution if \bigtriangleup = 0. So

\bigtriangleup = 0

k^{2} - 36 = 0

k^{2} = 36

k = \pm \sqrt{36}

k = \pm 6

For k = 6 or k = -6, the equation will have exactly one solution.

3 0
3 years ago
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