DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Answer:
<h2>
B. ST = 2</h2><h2 />
Step-by-step explanation:
|<-------------- 10 --------------------->|
S-------------------T--------------------U
X-6 2X - 8
FIND: ST
SOLUTION:
ST + TU = SU
x - 6 + 2x - 8 = 10
combine like terms:
3x - x = 10 + 8 + 6
x = 24/3
x = 8
plugin the value of x= 8 into the ST = x - 6
ST = x - 6
ST = 8 - 6
ST = 2
proof:
x - 6 + 2x - 8 = 10
8 - 6 + 2(8) - 8 = 10
10 = 10 ---OK
Answer:
512
Step-by-step explanation:
8 = 2^3
Therefore,
8^3
= (2^3)^3
= 2^(3*3)
= 2^9
= 512
Thus, 8^3 = 512
<h2>Please mark my answer as Brainliest!!!</h2>
POQ AND KLJ
They are the only alternate exterior angles
