Answer:
150 students.
No
.20
3/10
Step-by-step explanation:
What you do for the first one is you take 1,500 and times it by 90%. You will get 1,350. You will then take the 1350 and minus it from 1500 to get 150 students.
The next one says that he drilled a hole that is 5/9 inches wide. He has a drill bit that is 5/6. Will the drill bit be big enough. No because 5/9 is .556 and 5/6 is .833.
For the next one all they want you to do is look at the fruit percentage and put it into a decimal which is .20.
The next one they want the fraction that represents 30% which is 3/10.
Since V = (4/3) * pi * R^3
If R is halved, V' will reduce by a ratio of (1/2)^3 = 1/8
So V' = (1/8)V
Answer:
<em>The volume inside the giant sugar cube is 27 cubic feet.</em>
Step-by-step explanation:
It took 54 feet² of material to build the giant sugar cube. That means, the total surface area of the cube is 54 feet²
<u>Formula for surface area of a cube</u> is: 
, where 
is the length of each edge of the cube.
So, we will get.........
Now, <u>the volume of the cube will be</u>: 
feet³
Thus, the volume inside the giant sugar cube is 27 cubic feet.
For this case we must simplify the following expression:
![\sqrt [3] {64 * a ^ 6 * b ^ 7 * c ^ 9}](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B64%20%2A%20a%20%5E%206%20%2A%20b%20%5E%207%20%2A%20c%20%5E%209%7D)
We rewrite:
So:
![\sqrt [3] {4 ^ 3 * (a ^ 2) ^ 3 * (b ^ 2) ^ 3 * b * (c ^ 3) ^ 3} =\\\sqrt [3] {4 * a ^ 2 * b ^ 2 * c ^ 3) ^ 3 * b} =](https://tex.z-dn.net/?f=%5Csqrt%20%5B3%5D%20%7B4%20%5E%203%20%2A%20%28a%20%5E%202%29%20%5E%203%20%2A%20%28b%20%5E%202%29%20%5E%203%20%2A%20b%20%2A%20%28c%20%5E%203%29%20%5E%203%7D%20%3D%5C%5C%5Csqrt%20%5B3%5D%20%7B4%20%2A%20a%20%5E%202%20%2A%20b%20%5E%202%20%2A%20c%20%5E%203%29%20%5E%203%20%2A%20b%7D%20%3D)
By definition of properties of powers and roots we have:
![\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20m%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bm%7D%20%7Bn%7D%7D)
So:
![4a ^ 2b ^ 2 c ^ 3 \sqrt [3] {b}](https://tex.z-dn.net/?f=4a%20%5E%202b%20%5E%202%20c%20%5E%203%20%5Csqrt%20%5B3%5D%20%7Bb%7D)
Answer:
Option B
Use Bidmas, solve all the inner brackets (), with first division, then multiplication then addition then subtraction
