Question

The function g(x) is defined as g(x) = 6x2 + 23x – 4. When does g(x) = 0? x = –6 or x = StartFraction 1 Over 4 EndFraction x = –4 or x = StartFraction 1 Over 6 EndFraction x = StartFraction negative 1 Over 4 EndFraction or x = 6 x = StartFraction negative 1 Over 6 EndFraction or x = 4

Answer 1

Answer:

the answer is B Good LUCK :)

Step-by-step explanation:

Answer 2

Answer:

$g(x)=0$ when $x=-4$ and  $x=\frac{1}{6}$

Step-by-step explanation:

When $g(x)=0$

$6x^2+23x-4=0$

This is a quadratic equation and we solve it using the quadratic formula which says for $ax^2+bx+c=0$

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

in our case

$a=6\\b=23\\c=-4$

so we put those in and get:

$x=\frac{-23\pm\sqrt{23^2-4(6)(-4)} }{2(6)}=\frac{-23\pm25}{12}$

$\boxed{x=-4}\\\boxed{ x=1/6}$